Question

我有一个用Windows调度程序自动运行的程序。此程序运行使用昨天日期的存储过程，对我们的数据库运行查询以从前一天提取结果。此查询排除了一整天的特定时间段，因为我们不关心这些结果。但是，星期天我们有不同的小时数，并希望更改星期日的查询...有没有办法以不同的方式查询它是否是“星期日”？以下是我的存储过程：

CREATE PROCEDURE [dbo].[sp_Open_Close_Report_1] AS
declare   @dtNow         datetime ,   @dtToday       datetime ,   @dtFrom        datetime ,   @dtThru        datetime ,   @dtExcludeFrom datetime ,   @dtExcludeThru datetime, @dtExcludeEOD datetime 
set @dtNow         = getdate() 
set @dtToday       = convert(datetime,convert(varchar,@dtNow,112),112) 
set @dtFrom        = dateadd(day,-1,@dtToday) -- start-of-day yesterday 
set @dtThru        = dateadd(ms,-3,@dtToday)  -- end-of-day yesterday (e.g., 2012-06-17 23:59:59.997) 
set @dtExcludeFrom = convert(datetime, convert(char(10),@dtFrom,120) + ' 05:30:00.000' , 120 ) 
set @dtExcludeThru = convert(datetime, convert(char(10),@dtFrom,120) + ' 06:15:00.000' , 120 ) 
set @dtExcludeEOD = convert(datetime, convert(char(10),@dtFrom,120) + ' 08:00:00.000' , 120 ) 


SELECT Store_Id , DM_Corp_Received_Date, Register_Transaction_Type 
FROM Register_Till_Count_Tb 
WHERE (Register_Transaction_Type    =  'SOD' and store_ID = '12345'
AND DM_Corp_Received_date     between @dtFrom        
and @dtThru   
AND DM_Corp_Received_date not between @dtExcludeFrom 
and @dtExcludeThru) or (Register_Transaction_Type = 'EOD' and Store_ID='12345'
AND DM_Corp_Received_date Between @dtFrom and @dtThru)

星期日，@DTExclude来自6:30，@dtexcludeThru将是7:15

Answer 1

让我们做更多的数学运算，将所有内容保留为日期时间（或整数），而不是用字符串来捣乱：

declare   @dtNow         datetime ,   @dtToday       datetime ,   @dtFrom        datetime ,   @dtThru        datetime ,   @dtExcludeFrom datetime ,   @dtExcludeThru datetime, @dtExcludeEOD datetime 
set @dtNow         = getdate() 
set @dtToday       = DATEADD(day,DATEDIFF(day,0,@dtNow),0)
set @dtFrom        = dateadd(day,-1,@dtToday)

declare @Sunday int
set @Sunday = CASE WHEN DATEPART(weekday,@dtFrom) = DATEPART(weekday,'20120805') THEN 1 ELSE 0 END
set @dtExcludeFrom = DATEADD(minute,330 + @Sunday * 60,@dtFrom)
set @dtExcludeThru = DATEADD(minute,375 + @Sunday * 60,@dtFrom)
set @dtExcludeEOD = DATEADD(minute,480,@dtFrom)

并且，在您的查询中，而不是：

column between @dtFrom and @dtThru

使用：

column >= @dtFrom and column < @dtToday

Answer 2

查看datename和datepart函数。您可以使用if语句根据当天的情况执行不同的逻辑。当在星期天运行时，他们将产生这些结果：

select datename(dw, getdate()) -- Sunday
select datepart(dw, getdate()) -- 1

如何根据星期几运行不同的查询

2 个答案: