我有这些表格(简化):
Appointment(
INT idAppointment,
DATETIME start,
DATETIME end)
AppointmentInvolved(
INT idAppointment,
INT idInvolved)
Involved(
INT idInvolved,
VARCHAR name,
INT type,
INT idIncident)
Incident(
INT idIncident,
VARCHAR description)
有一个事件,可能有几个涉及它。每个Involved可以有多个约会,每个约会可以由多个Involved注册。涉及的类型(本例中为principal = 1,secondary = 2)。
鉴于idinointment我需要知道该事件中涉及的委托人,无论他是否将参加该特定任命。
到目前为止:
SELECT(*)
FROM Appointments a
INNER JOIN (AppointmentInvolved ai) ON ai.idAppointment = a.idAppointment,
INNER JOIN (Involved i) ON i.idInvolved = ai.idInvolved,
INNER JOIN (Incident in) ON i.idIncident = in.idIncident,
WHERE a.idAppointment = <WHATEV>
WHERE in.type=1
除非所涉及的校长要参加这项任命,否则这显然是行不通的。
这是某种自我加入吗?我并不真的需要Incident表,因为Involved人员可以通过idInvolved直接关联。
谢谢!
答案 0 :(得分:0)
SELECT *
FROM Involved I
WHERE I.type=1
AND I.idIncident IN (SELECT I2.idIncident
FROM AppointmentInvolved AI
INNER JOIN Involved I2 ON AI.idInvolved = I2.idInvolved
WHERE AI.idAppointment=<WHATEV>)