说我查询表
rawStats = Stats::TrackProcessed.select("token")
并收到表中所有令牌的数量。
看起来像这样:
3e79a387c29bda1069271e06ad03d82b8296242e
059681f46ab1c1fa8cf8443a82f0898172e0b646
eacd846ea4e91b49f92f416f61e0f2d075b9dae7
eacd846ea4e91b49f92f416f61e0f2d075b9dae7
811705019a970929801adbf3db0ede31ed01816c
我需要返回一个看起来像这样的哈希列表
{
'3e79a387c29bda1069271e06ad03d82b8296242e' => 1,
'059681f46ab1c1fa8cf8443a82f0898172e0b646' => 1
'eacd846ea4e91b49f92f416f61e0f2d075b9dae7' => 2
'811705019a970929801adbf3db0ede31ed01816c' => 1
}
第一个值是一个标记,第二个值是表中该标记的出现次数。 然后我需要从所有记录中获得平均值。
到目前为止,我已经使用
查询表了rawStats = Stats::TrackProcessed.select("distinct token")
通过检索唯一标记
然后每个循环计算每个标记的出现次数
rawArr = []
rawStats.each do |r|
token = {
:token => r.token,
:count => rawStats.where("token = ?",r.token).count('token')
}
rawArr << token
end
但这个过程为
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '196e595b573f71fc2af04693c73809303bebd62d'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'db67ab44e94ca338d90e902a36c37b4998a47ff0'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'a8a78cffc0935b07f90b5f3008dcad27e8ac71c7'
(0.8ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '91b8ae5ffa12ece30d8548b488fab8aff7614f2b'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '649e7aa59cc8af6c59cec1cf637ffed1ce6b3be7'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '441dae6f22776687b57daaaeef2c63c31902b987'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '6b8937a13012f22c8a4cdd4ed4caad0ad8761d3b'
(0.6ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'beaba154f38d5c9b64e4fb2d851ec785bd6bc4ec'
(0.6ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'efa9f3a71c4ff33abcae4af788ef6d0be599f76a'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '053a7727885f3c4099a9b31a2eccc77b99df50ee'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = '32dc984c9f85ff91242533144cd179a9b4529bed'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'a58804ae38490f08a1645c8271e88df3757fe771f'
(0.7ms) SELECT COUNT(`stats_track_processed`.`token`) FROM `stats_track_processed` WHERE `stats_track_processed`.`token` = 'a58804a2e38490f08a1645c8271e88df3757fe771f'
通过在处理大量数据时单独查询每个令牌,这看起来非常糟糕。
我已经通过SQL查询完成了这个,看起来像这样
SELECT AVG(viewsAverage) as total
FROM
(SELECT COUNT(token) AS viewsAverage
FROM stats_track_processed
WHERE admedia_id = #{params[:admedia_id]}
AND #{params[:banner_id]}
AND (access_time BETWEEN '#{params[:begin]}'
AND DATE_ADD('#{params[:end]}', INTERVAL 1 DAY))
GROUP BY token)
stats_track_processed
但这看起来真是一个糟糕的解决方案,我现在正在重构代码并将所有逻辑移动到控制器。
非常感谢任何帮助。
提前谢谢。
答案 0 :(得分:2)
试试这个
Stats::TrackProcessed.select(:token).count(group: :token)
欢呼声。
答案 1 :(得分:1)
您可以在单个查询中实现此目的:
SELECT SUM(IF(token = '196e595b573f71fc2af04693c73809303bebd62d', 1, 0)) AS token_1,
SUM(IF(token = 'db67ab44e94ca338d90e902a36c37b4998a47ff0', 1, 0)) AS token_2,
...
FROM `stats_track_processed`
WHERE `stats_track_processed`.`token` IN('196e595b573f71fc2af04693c73809303bebd62d',
'db67ab44e94ca338d90e902a36c37b4998a47ff0', ...);
或
SELECT token,
COUNT(token) AS token_count
FROM stats_track_processed
GROUP BY token;
答案 2 :(得分:1)
遍历完整列表并维护计数的哈希值。
result = Stats::TrackProcessed.select("token")
counts = Hash.new{|h,k| h[k] = 0 }
result.each{|el| counts[el] +=1}
然后要获得平均值,您可以执行类似
的操作 average = counts.values.inject(0){|sum, el| sum + el} / counts.length