SIMD以下代码

Question

如何在C中简化以下代码（当然使用SIMD内在函数）？我无法理解SIMD内在函数，这会有很大帮助：

int sum_naive( int n, int *a )
{
    int sum = 0;
    for( int i = 0; i < n; i++ )
        sum += a[i];
    return sum;
}

Answer 1

这是一个相当简单的实现（警告：未经测试的代码）：

int32_t sum_array(const int32_t a[], const int n)
{
    __m128i vsum = _mm_set1_epi32(0);       // initialise vector of four partial 32 bit sums
    int32_t sum;
    int i;

    for (i = 0; i < n; i += 4)
    {
        __m128i v = _mm_load_si128(&a[i]);  // load vector of 4 x 32 bit values
        vsum = _mm_add_epi32(vsum, v);      // accumulate to 32 bit partial sum vector
    }
    // horizontal add of four 32 bit partial sums and return result
    vsum = _mm_add_epi32(vsum, _mm_srli_si128(vsum, 8));
    vsum = _mm_add_epi32(vsum, _mm_srli_si128(vsum, 4));
    sum = _mm_cvtsi128_si32(vsum);
    return sum;
}

请注意，输入数组a[]需要16字节对齐，n应为4的倍数。