我正在努力解决这个错误:
08-08 11:42:53.179:E / AndroidRuntime(20288):引起:java.lang.InstantiationException:无法实例化类com.example.localnotificationtest.ReminderService;没有空构造函数
我不明白为什么会出现这种错误。
我正在尝试在特定时间显示通知,并在搜索一段时间后发现此old stackoverflow question。我尝试了一切,但我的代码给出了错误。
请帮我解决这个问题。
这是我的MainActivity代码:
public class MainActivity extends Activity {
int mHour, mMinute;
ReminderService reminderService;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
reminderService = new ReminderService("ReminderService");
TimePickerDialog dialog = new TimePickerDialog(this, mTimeSetListener, mHour, mMinute, false);
dialog.show();
}
TimePickerDialog.OnTimeSetListener mTimeSetListener = new OnTimeSetListener() {
@Override
public void onTimeSet(TimePicker v, int hourOfDay, int minute) {
mHour = hourOfDay;
mMinute = minute;
AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
Calendar c = Calendar.getInstance();
c.set(Calendar.YEAR, Calendar.YEAR);
c.set(Calendar.MONTH, Calendar.MONTH);
c.set(Calendar.DAY_OF_MONTH, Calendar.DAY_OF_MONTH);
c.set(Calendar.HOUR_OF_DAY, mHour);
c.set(Calendar.MINUTE, mMinute);
c.set(Calendar.SECOND, 0);
long timeInMills = c.getTimeInMillis();
Intent intent = new Intent(MainActivity.this, ReminderService.class);
PendingIntent pendingIntent = PendingIntent.getService(MainActivity.this, 0, intent, 0);
alarmManager.set(AlarmManager.RTC, timeInMills, pendingIntent);
}
};
}
这是我的ReminderService代码:
public class ReminderService extends IntentService {
public ReminderService(String name) {
super(name);
// TODO Auto-generated constructor stub
}
@Override
protected void onHandleIntent(Intent intent) {
Intent notificationIntent = new Intent(this, MainActivity.class);
PendingIntent contentIntent = PendingIntent.getActivity(this, 1, notificationIntent, PendingIntent.FLAG_CANCEL_CURRENT);
NotificationManager nm = (NotificationManager) this.getSystemService(Context.NOTIFICATION_SERVICE);
Notification.Builder builder = new Notification.Builder(this);
builder.setContentIntent(contentIntent)
.setSmallIcon(R.drawable.ic_launcher)
.setTicker("Local Notification Ticker")
.setWhen(System.currentTimeMillis())
.setAutoCancel(true)
.setContentTitle("Local Notification")
.setContentText("This is content text.");
Notification n = builder.getNotification();
nm.notify(1, n);
}
}
这是我的manifest.xml:
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.localnotificationtest"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="11"
android:targetSdkVersion="15" />
<application
android:icon="@drawable/ic_launcher" android:label="@string/app_name" android:theme="@style/AppTheme" >
<activity android:name=".MainActivity" android:label="@string/title_activity_main" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<service android:name="ReminderService"></service>
</application>
</manifest>
我不知道我哪里错了。我错过了一些代码吗?
答案 0 :(得分:216)
您需要在类中添加一个空构造函数,即。一个不带参数的人:
public ReminderService() {
super("ReminderService");
}
来自documentation的说明:
name
用于命名工作线程。
注意 :这仅适用于意向服务。
答案 1 :(得分:42)
如果您将服务声明为内部类/嵌套类,则还需要使类静态
如果没有它,即使你的构造函数是正确的,你也会得到错误
<强>解释强>
原因是,你只能实例化内部类 外部类的上下文,因此您需要创建一个实例 首先是外层阶级。
声明内部类静态使其独立于外部类
答案 2 :(得分:32)
为 IntentService
声明默认无参数构造函数public class ReminderService extends IntentService {
public ReminderService() {
super("ReminderService");
}
}
答案 3 :(得分:7)
您需要将默认无参数构造函数添加到 ReminderService 类。如果你不编写自己的构造函数(你有),则只会隐式添加。见这里:http://docs.oracle.com/javase/tutorial/java/javaOO/constructors.html