Question

希望还有其他人一直在使用点燃的数据表交叉手指 ...我已经尝试了一段时间了，为什么它不让我使用PHP值没有任何意义根本 - ＆gt;

include $DOCUMENT_ROOT.'/include/config.inc';
include $DOCUMENT_ROOT.'/include/session_check.inc';

require_once($DOCUMENT_ROOT.'/include/Datatables.php');
$datatables = new Datatables();

// MYSQL configuration
$config = array(
'username' => $dbuser,
'password' => $dbpass,
'database' => $dbname,
'hostname' => $dbhost);

$datatables->connect($config);

$datatables
->select('users.id as user_id, users.name as realname, users.username as username, users.email as email, users.phone as phone, domain.name as domain_name')
->from('users')
->join('domain', 'domain.id = users.domain_id', 'left')
->where('users.domain_id = "$domain_id"')
->add_column('available', '$1', 'available(available)')
->add_column('edit', '<a href="/wh.php?edit=1&id=$1" title="Purge the info for this Stock"><img src="/images/icons/dark/pencil.png" border="0"></a>', 'stock_id')
->unset_column('user_id');

echo $datatables->generate();

现在，$ domain_id的值根本不可用。我不知道我错误地说错，或者这种字符串组合是否可以接受？

Answer 1

好吧..我的错误......而不是行

->where('users.domain_id = "$domain_id"')

我应该用这个

->where('users.domain_id', $domain_id)

现在它运行得很好..无论如何： - ）

将php值解析为点燃的数据表

1 个答案: