是否可以拆分数组并将分裂注入？

Question

好的，我需要的是有点奇怪，如下：

手动创建线索数组，动态创建数据数组。 Xpath函数将我们的线索作为输入，并将结果映射到数据以创建动态数组

clues = Array.new

clues << 'Power supply type'    
clues << 'Slots'
clues << 'Software included'

selector = "//td[text()='%s']/following-sibling::td"

data = Array.new
data = clues.map do |clue| 
         xpath = selector % clue
         [clue, doc.at(xpath).text.strip]
       end

数据数组中的代码使用两个输入，线索和选择器
clues [index]中的每一项都进入％s的选择器变为

//td[text()='%s']/following-sibling::td  
//td[text()='Power supply type']/following-sibling::td
//td[text()='Slots']/following-sibling::td
//td[text()='Software included']/following-sibling::td

Xpath然后关闭并使用我们存储的命令从网页抓取信息，所有这些都作为数据存储为数组数据中的元素[0] ... data [3]

数据[2]看起来像这样，是一大块信息

Symantec Norton Internet Security (60 days live update); Recovery partition (inc
luding possibility to recover system; applications and drivers separately); Opti
onal re-allocation of recovery partition;

我想把这里列出的每一件软件都存放在自己的软件上，例如

data[2]Symantec Norton Internet Security (60 days live update); 
data[3]Recovery partition (including possibility to recover system; 
data[4]Optional re-allocation of recovery partition;

所以我假设我需要以某种方式分割数据[2]并将其添加回数据数组中？

我正在尝试隔离这个特定的索引，因为我需要在多行上为我的最终输出到电子表格

最终所需输出

Answer 1

为了澄清，你有一个这样的数组：

data << 'Power supply type'
data << 'Slots'
data << 'Symantec Norton Internet Security (60 days live update); Recovery partition (inc luding possibility to recover system; applications and drivers separately); Optional re-allocation of recovery partition;'
data << 'Something else'

你想要它变成这个吗？

data << 'Power supply type'
data << 'Slots'
data << Symantec Norton Internet Security (60 days live update);
data << Recovery partition (inc luding possibility to recover system;
data << applications and drivers separately);
data << Optional re-allocation of recovery partition;
data << 'Something else'

您可以通过执行以下操作来执行此操作：

temp = []
data[2].split(/(;)/).each_slice(2){ |s| temp << s.join.strip }
data[2] = temp
data.flatten!

或者，如果要迭代数据数组中的所有项目：

data.each_with_index do |x, i|
  temp = []
  data[i].split(/(;)/).each_slice(2){ |s| temp << s.join.strip }
  data[i] = temp
end
data.flatten!

基本上发生的事情是它需要字符串，将其分解为';'，重新插入';'删除它的地方，用分割字符串的数组替换数据数组中的原始点，然后将整个数据数组展平成一个数组。

Answer 2

data = Array.new
clues.each do |clue|
  xpath = selector % clue
  text = doc.at(xpath).text.strip
  if clue == 'Software included'
    values = text.scan(/.+?;/)
    values << text if values.empty? # text did not contain a semicolon
    data << [clue, values.shift.strip]
    values.each do |value|
      data << ['', value.strip]
    end
  else
    data << [clue, text]
  end
end

输出（缩进以便更具可读性）：

[
  ["Power supply type", "400w"],
  ["Slots", "2"],
  ["Software included", "Symantec Norton Internet Security (60 days live update);"],
  ["", "Recovery partition (including possibility to recover system;"],
  ["", "applications and drivers separately);"],
  ["", "Optional re-allocation of recovery partition;"]
]

Answer 3

data = data[0..1] + data[2].scan(/.*?;/) + data[3..-1]