从模型中排除项目 - MVC / ASP.Net

时间:2012-08-03 21:51:52

标签: asp.net asp.net-mvc linq entity-framework-4

这是this post

的后续问题

我有两种模式:

CarType.cs

//
// Holds types of car - this has a one to many relationship with Car class
//
[Table("tType")]
public class CarType
{
    [Key]
    public int type_id { get; set; }
    public int dealer_id { get; set; }
    public string type_name { get; set; }
    public string type_desc { get; set; }
    public virtual ICollection<Car> Cars { get; set; }
}  


Car.cs

//
// Holds actual Cars
//

[Table("tCar")]
public class Car
{
    [Key]
    public int car_id { get; set; }
    public int dealer_id { get; set; }
    public int type_id { get; set; }
    public int car_order { get; set; }
    public string car_name { get; set; }
    public virtual ICollection<Rental> Rentals { get; set; }
    public virtual CarType CarType { get; set; }
}

我希望有一个视图模型,我可以在其中查看汽车类型,以及每个汽车类型类中每种汽车类型的数量,因此我创建了一个ViewModel:

public class SearchViewModel
{
    [Required]
    public DateTime From { get; set; }
    public int Nights { get; set; }
    public int dealer_id { get; set; }
    public IQueryable<CarType> CarTypes { get; set; }
    // CarTypes as above, has a one to many relationship with the class Car
}

鉴于预先确定的实际汽车列表(比如preBookedCars),我想从ViewObject中删除汽车列表,例如,如果CarType模型(包括一个2辆汽车)看起来像这样:

Mercedes (count = 3)
....Car 1
....Car 2
....Car 3
Ford (count = 3)
....Car 4
....Car 5
....Car 6
Citroen (count = 3)
....Car 7
....Car 8
....Car 9

鉴于CARS列表,我如何从CarType模型中排除汽车列表 - 例如。

我有一个列表:汽车1,汽车4,汽车8,汽车9 - 所以我希望上面的模型显示:

Mercedes (count = 2)
....Car 2
....Car 3
Ford (count = 2)
....Car 5
....Car 6
Citroen (count = 1)
....Car 7

我知道这是(伪LINQ):

var freeCars = (db context).CarTypes
                        .Cars
                        .Except(preBookedCars)

感谢您的帮助,

标记

1 个答案:

答案 0 :(得分:2)

我不确定这是否是您正在寻找的,但如果您只想尝试过滤CarType对象中的Cars集合,则可以使用以下内容:

var preBookedCars = new List<int> { 1, 5, 9 };
var myCarType = new CarType();
var filteredCars = myCarType.Cars.Where(c => !preBookedCars.Contains(c.car_id));

此代码可以根据您的需要进行调整。