将数据从Access迁移到SQL Server。 SQL Server表将inst_id,cons_code和eff_date_time列定义为主键。来自访问的eff_date_time数据不是唯一的,所以我试图将秒字段增加一秒,所以我将有一个唯一的日期时间。我无法获得DATEADD将日期增加1秒。附上是我的代码。我做错了什么???
USE [CON-INST]
GO
DECLARE
@cv_InstId VARCHAR(25),
@cv_ConsCode VARCHAR(10),
@cv_EffDateTime DATETIME,
@lv_count INT
DECLARE BumpDate_Cursor CURSOR
STATIC
FOR
SELECT inst_id, cons_code, eff_date_time
FROM [CON-INST].[dba].[constants_temp]
ORDER BY inst_id
OPEN BumpDate_Cursor
FETCH FIRST FROM BumpDate_Cursor
INTO @cv_InstId, @cv_ConsCode, @cv_EffDateTime
SET @lv_count = 1
// Debug statements
PRINT '@cv_InstId = ' + @cv_InstId
PRINT '@cv_ConsCode = ' + @cv_ConsCode
PRINT '@cv_EffDateTime = ' + CONVERT(VARCHAR, @cv_EffDateTime)
PRINT '@lv_count = ' + CONVERT(VARCHAR, @lv_count)
-- Loop to iterate thru instruments identifying the various constant
types that are needed, i.e. the column names - constant 1, constant 2,
constant 3, station, offset, etc.
WHILE @@FETCH_STATUS = 0
-- do processing
BEGIN
PRINT '@lv_count before = ' + CONVERT(VARCHAR, @lv_count)
PRINT CONVERT(VARCHAR, @cv_EffDateTime, 121)
IF (CONVERT(VARCHAR, @cv_EffDateTime,121) = '1901-01-01 17:00:00.000')
BEGIN
UPDATE [CON-INST].[dba].[constants_temp]
SET eff_date_time = DATEADD(second, @lv_count, eff_date_time)
WHERE inst_id = @cv_InstId and cons_code = @cv_ConsCode;
PRINT CONVERT(VARCHAR, @cv_EffDateTime, 121)
END
FETCH NEXT FROM BumpDate_Cursor
INTO @cv_InstId, @cv_ConsCode, @cv_EffDateTime
SET @lv_count = @lv_count + 1
PRINT '@lv_count after = ' + CONVERT(VARCHAR, @lv_count)
END
CLOSE BumpDate_Cursor
DEALLOCATE BumpDate_Cursor
更新前表格中的数据
inst_id cons_code eff_date_time constant entry_user输入代码entry_date update_user update_date
1 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:07:33.770 NULL NULL
1 PU 1901-01-01 17:00:00.000 821.6 dba 2012-08-02 11:07:33.770 NULL NULL
1 PU 1901-01-01 17:00:00.000 8 dba 2012-08-02 11:07:33.770 NULL NULL
1 PU 1901-01-01 17:00:00.000 2251 dba 2012-08-02 11:07:33.770 NULL NULL
2 PU 1901-01-01 17:00:00.000 2251 dba 2012-08-02 11:07:33.770 NULL NULL
2 PU 1901-01-01 17:00:00.000 22 dba 2012-08-02 11:07:33.770 NULL NULL
2 PU 1901-01-01 17:00:00.000 820.9 dba 2012-08-02 11:07:33.773 NULL NULL
2 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:07:33.773 NULL NULL
3 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:07:33.773 NULL NULL
3 PU 1901-01-01 17:00:00.000 821.5 dba 2012-08-02 11:07:33.773 NULL NULL
3 PU 1901-01-01 17:00:00.000 8 dba 2012-08-02 11:07:33.773 NULL NULL
3 PU 1901-01-01 17:00:00.000 2095 dba 2012-08-02 11:07:33.773 NULL NULL
4 PU 1901-01-01 17:00:00.000 2095 dba 2012-08-02 11:07:33.777 NULL NULL
4 PU 1901-01-01 17:00:00.000 22 dba 2012-08-02 11:07:33.777 NULL NULL
4 PU 1901-01-01 17:00:00.000 820.5 dba 2012-08-02 11:07:33.777 NULL NULL
4 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:07:33.777 NULL NULL
A PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:07:33.777 NULL NULL
A PU 1901-01-01 17:00:00.000 816.8 dba 2012-08-02 11:07:33.777 NULL NULL
A PU 1901-01-01 17:00:00.000 120.5 dba 2012-08-02 11:07:33.780 NULL NULL
A PU 1901-01-01 17:00:00.000 2255 dba 2012-08-02 11:07:33.780 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 1492 dba 2012-08-02 11:07:33.780 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 986.48 dba 2012-08-02 11:07:33.780 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:07:33.780 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:07:33.780 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 986.48 dba 2012-08-02 11:07:33.780 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 1857 dba 2012-08-02 11:07:33.780 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 1896 dba 2012-08-02 11:07:33.783 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 986.5 dba 2012-08-02 11:07:33.783 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:07:33.783 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:07:33.783 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 986.5 dba 2012-08-02 11:07:33.783 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 1936 dba 2012-08-02 11:07:33.783 NULL NULL
执行期间PRINT语句的输出
@cv_InstId = 1
@cv_ConsCode = PU
@cv_EffDateTime = 1901年1月1日下午5:00
@lv_count = 1
更新前:1901-01-01 17:00:00.000
@lv_count = 2
更新前:1901-01-01 17:00:00.000
@lv_count = 3
更新前:1901-01-01 17:00:00.000
@lv_count = 4
更新前:1901-01-01 17:00:00.000
@lv_count = 5
更新前:1901-01-01 17:00:00.000
@lv_count = 6
更新前:1901-01-01 17:00:00.000
@lv_count = 7
更新前:1901-01-01 17:00:00.000
@lv_count = 8
更新前:1901-01-01 17:00:00.000
@lv_count = 9
更新前:1901-01-01 17:00:00.000
@lv_count = 10
更新前:1901-01-01 17:00:00.000
@lv_count = 11
更新前:1901-01-01 17:00:00.000
@lv_count = 12
更新前:1901-01-01 17:00:00.000
@lv_count = 13
更新前:1901-01-01 17:00:00.000
@lv_count = 14
更新前:1901-01-01 17:00:00.000
@lv_count = 15
更新前:1901-01-01 17:00:00.000
@lv_count = 16
更新前:1901-01-01 17:00:00.000
@lv_count = 17
更新前:1901-01-01 17:00:00.000
@lv_count = 18
更新前:1901-01-01 17:00:00.000
@lv_count = 19
更新前:1901-01-01 17:00:00.000
@lv_count = 20
更新前:1901-01-01 17:00:00.000
@lv_count = 21
更新前:1972-07-01 00:00:00.000
@lv_count = 22
更新前:1972-07-01 00:00:00.000
@lv_count = 23
更新前:1972-07-01 00:00:00.000
@lv_count = 24
更新前:1972-07-01 00:00:00.000
@lv_count = 25
更新前:1972-07-01 00:00:00.000
执行后的表格输出
inst_id cons_code eff_date_time constant entry_user entry_date update_user update_date
1 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:28:27.287 NULL NULL
1 PU 1901-01-01 17:00:00.000 821.6 dba 2012-08-02 11:28:27.287 NULL NULL
1 PU 1901-01-01 17:00:00.000 8 dba 2012-08-02 11:28:27.290 NULL NULL
1 PU 1901-01-01 17:00:00.000 2251 dba 2012-08-02 11:28:27.290 NULL NULL
2 PU 1901-01-01 17:00:00.000 2251 dba 2012-08-02 11:28:27.290 NULL NULL
2 PU 1901-01-01 17:00:00.000 22 dba 2012-08-02 11:28:27.290 NULL NULL
2 PU 1901-01-01 17:00:00.000 820.9 dba 2012-08-02 11:28:27.290 NULL NULL
2 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:28:27.290 NULL NULL
3 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:28:27.290 NULL NULL
3 PU 1901-01-01 17:00:00.000 821.5 dba 2012-08-02 11:28:27.290 NULL NULL
3 PU 1901-01-01 17:00:00.000 8 dba 2012-08-02 11:28:27.290 NULL NULL
3 PU 1901-01-01 17:00:00.000 2095 dba 2012-08-02 11:28:27.293 NULL NULL
4 PU 1901-01-01 17:00:00.000 2095 dba 2012-08-02 11:28:27.293 NULL NULL
4 PU 1901-01-01 17:00:00.000 22 dba 2012-08-02 11:28:27.293 NULL NULL
4 PU 1901-01-01 17:00:00.000 820.5 dba 2012-08-02 11:28:27.293 NULL NULL
4 PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:28:27.293 NULL NULL
A PU 1901-01-01 17:00:00.000 833.2 dba 2012-08-02 11:28:27.293 NULL NULL
A PU 1901-01-01 17:00:00.000 816.8 dba 2012-08-02 11:28:27.293 NULL NULL
A PU 1901-01-01 17:00:00.000 120.5 dba 2012-08-02 11:28:27.297 NULL NULL
A PU 1901-01-01 17:00:00.000 2255 dba 2012-08-02 11:28:27.297 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 1492 dba 2012-08-02 11:28:27.297 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 986.48 dba 2012-08-02 11:28:27.297 NULL NULL
A-1 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.297 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.297 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 986.48 dba 2012-08-02 11:28:27.300 NULL NULL
A-10 AS 1972-07-01 00:00:00.000 1857 dba 2012-08-02 11:28:27.300 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 1896 dba 2012-08-02 11:28:27.300 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 986.5 dba 2012-08-02 11:28:27.300 NULL NULL
A-11 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.300 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.300 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 986.5 dba 2012-08-02 11:28:27.300 NULL NULL
A-12 AS 1972-07-01 00:00:00.000 1936 dba 2012-08-02 11:28:27.300 NULL NULL
A-13 AS 1972-07-01 00:00:00.000 1976 dba 2012-08-02 11:28:27.300 NULL NULL
A-13 AS 1972-07-01 00:00:00.000 986.46 dba 2012-08-02 11:28:27.300 NULL NULL
A-13 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.303 NULL NULL
A-14 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.303 NULL NULL
A-14 AS 1972-07-01 00:00:00.000 986.48 dba 2012-08-02 11:28:27.303 NULL NULL
A-14 AS 1972-07-01 00:00:00.000 2016 dba 2012-08-02 11:28:27.303 NULL NULL
A-15 AS 1972-07-01 00:00:00.000 0 dba 2012-08-02 11:28:27.303 NULL NULL
答案 0 :(得分:0)
代码中有一些问题,但主要的是更新语句 - 它一次更新数据库中的多个记录。例如,当循环运行第一次更新时,它会更新四个记录,其中inst_id ='1'和const_code ='PU',每个记录添加1秒。在第二次迭代中,它然后为所有四个记录增加2秒,对第三次迭代的所有四个记录增加3秒,最后对第四次迭代的所有四个记录增加4秒(使所有记录都为1 + 2 + 3 + 4) =下午5点后10秒。)
最佳解决方案是添加一个新列ID,其类型为INT IDENITY PRIMARY KEY,并将复合主键放在inst_id,cons_code和eff_date_time列上。
但是,如果由于某种原因,您必须在这三个字段上使用复合主键,那么这是执行此操作的代码。
注意:您不能只为每个日期添加一些唯一的数字,因为您可能会达到这样的程度,即您实际上与表中遇到的另一个值相冲突。这就是代码EXISTS部分的原因。
drop table [constants_temp]
go
drop table [constants_new]
go
create table [constants_temp] (
inst_id varchar(25),
cons_code varchar(10),
eff_date_time datetime
)
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('1', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('1', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('1', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('1', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('2', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('2', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('2', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('2', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('3', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('3', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('3', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('3', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('4', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('4', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('4', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('4', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A', 'PU', '1901-01-01 17:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-1', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-1', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-1', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-10', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-10', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-10', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-11', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-11', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-11', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-12', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-12', 'AS', '1972-07-01 00:00:00.000')
insert into [constants_temp] (inst_id, cons_code, eff_date_time) values ('A-12', 'AS', '1972-07-01 00:00:00.000')
-- Create a table with the idential structure as [constants_temp], except with the composite primary key on all three fields
create table [constants_new] (
inst_id varchar(25),
cons_code varchar(10),
eff_date_time datetime,
PRIMARY KEY (inst_id, cons_code, eff_date_time)
)
-- Variables to hold the column values from each row in the cursor
DECLARE @Cur_inst_id VARCHAR(25)
DECLARE @Cur_cons_code VARCHAR(10)
DECLARE @Cur_eff_date_time DATETIME
-- Go through all of the records in the [constants_temp] table
DECLARE BumpDate_Cursor CURSOR FOR
SELECT inst_id,
cons_code,
eff_date_time
FROM [constants_temp]
ORDER BY inst_id, cons_code, eff_date_time
-- Open the cursor and get the first record
OPEN BumpDate_Cursor
FETCH NEXT FROM BumpDate_Cursor INTO @Cur_inst_id, @Cur_cons_code, @Cur_eff_date_time
-- For all the the records in the cursor...
WHILE @@FETCH_STATUS = 0
BEGIN
-- While there is already a record with a matching institution code, cons code, and effective date...
WHILE EXISTS (SELECT inst_id
FROM [constants_new]
WHERE inst_id = @Cur_inst_id and
cons_code = @Cur_cons_code and
eff_date_time = @Cur_eff_date_time)
BEGIN
-- Keep incrementing the effective date by one second
set @Cur_eff_date_time = DATEADD(second, 1, @Cur_eff_date_time)
END
-- Insert the new unique row
INSERT INTO [constants_new] (inst_id, cons_code, eff_date_time) VALUES (@Cur_inst_id, @Cur_cons_code, @Cur_eff_date_time)
-- Get the next record in the cursor
FETCH NEXT FROM BumpDate_Cursor INTO @Cur_inst_id, @Cur_cons_code, @Cur_eff_date_time
END
-- Close and deallocate the cursor
CLOSE BumpDate_Cursor
DEALLOCATE BumpDate_Cursor
-- Show the results
select * from [constants_new] order by inst_id, cons_code, eff_date_time