我在youtube上观看了新浪的教程,所以现在我正在制作" Bucky's Land。"此代码目前允许我向左,向右,向上和向下移动我的角色。它根据移动方式改变玩家的侧面。我是java的初学者,我想知道如何让我的角色跳跃。任何帮助,将不胜感激!
package javagame;
import org.newdawn.slick.*;
import org.newdawn.slick.state.*;
public class Play extends BasicGameState{
Animation bucky, movingUp, movingDown, movingLeft, movingRight;
Image worldMap;
boolean quit = false;
int[] duration = {200,200};
float buckyPositionX = 0;
float buckyPositionY = 0;
float shiftX = buckyPositionX + 320;
float shiftY = buckyPositionY + 160;
boolean jumping = false;
float verticalSpeed = 0.0f;
public Play(int state){
}
public void init(GameContainer gc, StateBasedGame sbg) throws SlickException{
worldMap = new Image("res/world.png");
Image[] walkUp = {new Image("res/buckysBack.png"), new Image("res/buckysBack.png")};
Image[] walkDown = {new Image("res/buckysFront.png"), new Image("res/buckysFront.png")};
Image[] walkLeft = {new Image("res/buckysLeft.png"), new Image("res/buckysLeft.png")};
Image[] walkRight = {new Image("res/buckysRight.png"), new Image("res/buckysRight.png")};
movingUp = new Animation(walkUp, duration, false);
movingDown = new Animation(walkDown, duration, false);
movingLeft = new Animation(walkLeft, duration, false);
movingRight = new Animation(walkRight, duration, false);
bucky = movingDown;
}
public void render(GameContainer gc, StateBasedGame sbg, Graphics g) throws SlickException{
worldMap.draw(buckyPositionX, buckyPositionY);
bucky.draw(shiftX, shiftY);
g.drawString("Buckys X: "+buckyPositionX+"\nBuckys Y: "+buckyPositionY, 400, 20);
if(quit==true){
g.drawString("Resume (R)", 250, 100);
g.drawString("Main Menu (M)", 250, 150);
g.drawString("Quit Game (Q)", 250, 200);
if(quit==false){
g.clear();
}
}
}
public void update(GameContainer gc, StateBasedGame sbg, int delta) throws SlickException{
Input input = gc.getInput();
if(input.isKeyDown(Input.KEY_UP)){
bucky = movingUp; //change bucky to up image
buckyPositionY += delta * .1f; //increase the Y coordinates of bucky (move him up)
if(buckyPositionY>162){
buckyPositionY -= delta * .1f; //dont let him keep going up if he reaches the top
}
}
if(input.isKeyDown(Input.KEY_DOWN)){
bucky = movingDown;
buckyPositionY -= delta * .1f;
if(buckyPositionY<-600){
buckyPositionY += delta * .1f;
}
}
if(input.isKeyDown(Input.KEY_LEFT)){
bucky = movingLeft;
buckyPositionX += delta * .1f;
if(buckyPositionX>324){
buckyPositionX -= delta * .1f;
}
}
if(input.isKeyDown(Input.KEY_RIGHT)){
bucky = movingRight;
buckyPositionX -= delta * .1f;
if(buckyPositionX<-840){
buckyPositionX += delta * .1f;
}
}
//when they hit escape
if(quit==true){
if(input.isKeyDown(Input.KEY_R)){
quit = false;
}
if(input.isKeyDown(Input.KEY_M)){
sbg.enterState(0);
try{
Thread.sleep(250);
}catch(InterruptedException e){
e.printStackTrace();
}
}
if(input.isKeyDown(Input.KEY_Q)){
System.exit(0);
}
}
}
public int getID(){
return 1;
}
}
答案 0 :(得分:1)
你需要一些物理学。这个想法是,当有人按下空格键时,你可以将角色的速度设置为例如5。每秒你从它减去1并将其加到角色的高度,直到他再次击中地面。您可能还希望将速度限制为(5,-5)