我正在尝试将oauth用于CX暴露的api,我按照他们的文档,我仍然得到HTTP“BAD REQUEST”错误,这是代码 -
String method = "POST";
String code = "";
NameValuePair[] data = {
new NameValuePair("grant_type", "authorization_code"),
new NameValuePair("code", code),
new NameValuePair("redirect_uri",URLEncoder.encode(CALLBACK_URL, "UTF-8"))
};
String secret = CONSUMER_KEY+":"+CONSUMER_SECRET;
String encodedSecret = Base64.encodeBase64String(secret.getBytes("UTF-8"));
org.apache.commons.httpclient.HttpClient httpClient = new org.apache.commons.httpclient.HttpClient();
PostMethod httpMethod = new PostMethod(ACCESS_TOKEN_ENDPOINT_URL);
httpMethod.addRequestHeader("Authorization","Basic "+encodedSecret);
httpMethod.setRequestBody(data);
System.out.println("HTTP call -- " + method + " " + ACCESS_TOKEN_ENDPOINT_URL);
httpClient.executeMethod(httpMethod);
谢谢, 与Hemant
答案 0 :(得分:0)
我测试了以下对代码的轻微修改,它确实有效。您可以仔细检查
尝试让auth_code响应和令牌请求的redirect_uri相同
String method = "POST";
String authCode = "[AUTH-CODE-HERE]";
String CONSUMER_KEY="[YOUR-KEY-HERE]";
String CONSUMER_SECRET="[YOUR-SECRET-HERE]";
String ACCESS_TOKEN_ENDPOINT_URL="https://api.cx.com/1/oauth/token";
String REDIRECT_URI="[YOUR-REDIRECT-HERE]";
NameValuePair[] data = {
new NameValuePair("grant_type", "authorization_code"),
new NameValuePair("code", authCode),
new NameValuePair("redirect_uri", REDIRECT_URI)
};
String secret = CONSUMER_KEY+":"+CONSUMER_SECRET;
String encodedSecret = Base64.encodeBase64String(secret.getBytes("UTF-8"));
PostMethod httpMethod = new PostMethod(ACCESS_TOKEN_ENDPOINT_URL);
httpMethod.addRequestHeader("Authorization","Basic "+encodedSecret);
httpMethod.setRequestBody(data);
System.out.println("HTTP call -- " + method + " " + ACCESS_TOKEN_ENDPOINT_URL);
int responseCode = httpClient.executeMethod(httpMethod);
System.out.println(responseCode);
System.out.println(httpMethod.getResponseBodyAsString());
如果您仍然遇到问题,可以发布以下行的结果:System.out.println(httpMethod.getResponseBodyAsString());
答案 1 :(得分:0)
CX开发人员API已停止使用。 很抱歉给您带来不便。