Question

我的桌子就像......

id  Sub_id  name    path    date

1   33  Sanjay  Something here to all   Some thing
2   33  Sanjay      
3   34  Fariya      
4   35  Neeraj      
5   35  Neeraj      
6   32  Mukesh      
7   37  Ravi        
8   32  Mukesh      
9   32  Mukesh      
10  32  Mukesh

当我使用此查询时 - 表名是gallery ...

$sql="select * from (select * from gallery order by id desc 4) gallery group by Sub_id desc limit 4";

我需要这种格式

id  Sub_id  name    path    date
10  32  Mukesh  Something here to all   Some thing
7   37  Ravi        
5   35  Neeraj      
3   34  Fariya

请帮帮我......

Answer 1

试试这个：

SELECT 
    MAX(id), 
    Sub_id, 
    name, 
    path, 
    date 
FROM 
    gallery 
GROUP BY 
    Sub_id
ORDER BY 
    id DESC 
LIMIT 4;

Answer 2

以原始SQL为基础（如果要先为id排序，再为sub_id排序）：

$sql="select * from gallery group by sub_id order by id desc, subid desc limit 0,4";

如果不打算消除“重复”，则可以使用以下sql代替上述sql：

$sql="select * from gallery order by id desc, subid desc limit 0,4";

Answer 3

请试试这个

select * from  (select max(id), sub_id from gallery group by sub_id order by id desc) where rownum <=4;

如何按降序排序id和sub_id？

3 个答案: