我有这段代码:
Dim myStream As Stream = Nothing
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "C:\Users\Desktop\Sample Pictures"
openFileDialog1.Filter = "Pictures|*.jpg|Text|*.txt"
If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
myStream = openFileDialog1.OpenFile()
If (myStream IsNot Nothing) Then
' Insert code to read the stream here.
End If
End Sub
End Class
我需要将 myStream 中的文件复制到某个目标文件夹。 知道如何实现它吗?
答案 0 :(得分:1)
你可以使用:
Image img = Image.FromStream(myStream);
或
Image img = Image.FromFile(path);
而且,除以:
img.Save("new location");
[样品在C#中]
答案 1 :(得分:1)
假设myDestinationDir
是您要复制文件的路径,那么
If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
' Extract the filename part from the full filename returned by openDialog.'
Dim selectedFile As String = Path.GetFileName(openFileDialog1.FileName)
' Append to the destinationDir the filename extracted'
Dim destFile As String = Path.Combine(myDestinationDir, selectedFile)
' Copy with overwrite (if overwrite is not desidered, use the overload with False as 3 arg'
System.IO.File.Copy(openFileDialog1.FileName, destFile)
End Sub
这会将所选文件复制到目标文件夹,覆盖具有相同名称的现有文件。
答案 2 :(得分:0)
这是我为一些实验软件编写的真实代码的片段。
Dim strPath As String
Dim fStream As FileStream
Dim fileName As String
Try
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'Get path from textbox
strPath = txtSavePath.Text.ToLower
'Check directory existence, if not, create it
If Directory.Exists(strPath) Then
Else
Try
Directory.CreateDirectory(strPath)
Catch ex As Exception
MessageBox.Show("Error in Creating Directory, Code : " & ex.ToString)
End Try
End If
'Set current active directory
Directory.SetCurrentDirectory(strPath)
'Create Filename
fileName = txtFileName.Text.ToUpper & "_" & DateTime.Now.ToString("yyyyMMdd_HH_mm_ss")
'Write/Create file
fStream = File.Open(fileName & ".png", FileMode.Create)
fStream.Write(byteData, 0, nLength)
fStream.Close()
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'Display On Window
picGraphDisplay.BackgroundImage = Image.FromFile(fileName & ".png")
txtSavedFileName.Text = fileName & ".png"
Catch ex As Exception
CheckVisaStatus(errorStatus)
MessageBox.Show(ex.ToString)
End Try
在这种情况下,文件流将图像的字节数据写入文件。从哪里获取字节图像取决于你。在这种情况下,一个好主意是为您的文件使用一个特定的名称,使用系统的DateTime.Now
在这里完成。
希望它能给你一些想法。干杯