我正在尝试序列化/反序列化复杂类型。我希望保留对象引用,这意味着如果在对象图中多次引用对象的实例,则在反序列化期间,我希望反序列化器仅创建该实例一次并多次引用它(与创建该对象实例相比)多次)。
我需要系统处理的第二件事是字典,其中键本身就是一个复杂的类型。
我能够通过DataContractSerializer序列化到XML来实现这两个目标。但是,我没有找到任何可以执行此操作的Json序列化程序。我尝试过Json.NET和ServiceStack,但没有运气。
请参阅下面的示例代码:
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Runtime.Serialization;
using System.Text;
using System.Xml;
using Newtonsoft.Json;
namespace Serialization
{
class Program
{
static void Main(string[] args)
{
var transportModel = CreateSampleModel();
//Serialize with DataContractSerializer
var serializer = new DataContractSerializer(typeof(TransportModel), null, int.MaxValue, false, true, null, null);
string serializedObjectXml;
using (var sw = new StringWriter())
{
using (var writer = new XmlTextWriter(sw))
{
serializer.WriteObject(writer, transportModel);
writer.Flush();
serializedObjectXml = sw.ToString();
}
}
//Deserialize with DataContractSerializer
byte[] byteArray = Encoding.ASCII.GetBytes(serializedObjectXml);
var stream = new MemoryStream(byteArray);
var deserializedObjectXml = serializer.ReadObject(stream);
//Serialize with Json.NET
var serializedObjectJson=JsonConvert.SerializeObject(transportModel);
//Deserialize with Json.NET - this fails because of the key in the dictionary being a complex type
var deserializedObjectJson = JsonConvert.DeserializeObject(serializedObjectJson);
}
static TransportModel CreateSampleModel()
{
var transportModel = new TransportModel();
// dests
var fra = new Destination
{
Id = 0,
Name = "FRA",
Demand = 900
};
var det = new Destination
{
Id = 1,
Name = "DET",
Demand = 1200
};
var dests = new List<Destination> { fra, det};
//origs
var gary = new Origin
{
Id = 0,
Name = "GARY",
Supply = 1400,
Cost = new Dictionary<Destination, int>{
{fra, 39},
{det, 14}
}
};
var origs = new List<Origin> { gary};
transportModel.Destinations = dests;
transportModel.Origins = origs;
return transportModel;
}
}
[DataContract]
class Destination
{
[DataMember]
public int Id { get; set; }
[DataMember]
public string Name { get; set; }
[DataMember]
public int Demand { get; set; }
}
[DataContract]
class Origin
{
[DataMember]
public int Id { get; set; }
[DataMember]
public string Name { get; set; }
[DataMember]
public int Supply { get; set; }
[DataMember]
public Dictionary<Destination, int> Cost { get; set; }
}
[DataContract]
class TransportModel
{
[DataMember]
public List<Origin> Origins;
[DataMember]
public List<Destination> Destinations;
public TransportModel()
{
Origins = new List<Origin>();
Destinations = new List<Destination>();
}
}
}
答案 0 :(得分:14)
Json.NET支持处理对象引用:Preserving Object References
复杂类型字典键可以通过创建TypeConverter来处理,该{{3}}将字符串转换为字符串。 Json.NET将使用该字符串作为字典键。
答案 1 :(得分:0)
使用.NET内置的BinaryFormatter,它可以保留引用。
虽然我个人不鼓励使用具有循环依赖性的对象图blob,但这种blob不可修改,内省并且几乎没有机会处理版本更改。
数据传输对象(即用于序列化的类型)理想情况下应该是流行的,可版本化的和容忍格式的干净,自我描述和序列化。