Question

我有一个简单的Spring Bean Expression，当我在应用程序上下文文件中定义它时评估很好：

<bean id="myConfigBean" class="com.example.myBeanConfigBean">
    <property name="myProperty" value="#{ someOtherBean.getData() }"/>
</bean>

现在，我想以编程方式进行相同的评估。我使用了以下代码：

final ExpressionParser parser = new SpelExpressionParser();
final TemplateParserContext templateContext = new TemplateParserContext();
Expression expression = parser.parseExpression("#{ someOtherBean.getData() }", templateContext);
final String value = (String) expression.getValue();

这会引发异常：

EL1007E:(pos 22): Field or property 'someOtherBean' cannot be found on null

我想我必须以某种方式设置一个根对象，允许配置的bean像属性一样。但我还没有让它工作。任何人，已经做过这个并且可以提示一下吗？

Answer 1

实现BeanFactoryAware以获取对bean工厂的引用;然后...

StandardEvaluationContext context = new StandardEvaluationContext();
context.setBeanResolver(new BeanFactoryResolver(this.beanFactory));
Expression expression = parser.parseExpression("@someOtherBean.getData()"); 
// or "@someOtherBean.data"
final String value = expression.getValue(context, String.class);

修改

回答以下评论。 @触发使用bean工厂解析器来访问bean;另一种方法是在评估上下文中添加BeanExpressionContextAccessor并使用BeanExpressionContext作为评估的根对象......

final ExpressionParser parser = new SpelExpressionParser(); StandardEvaluationContext context = new StandardEvaluationContext(); context.setBeanResolver(new BeanFactoryResolver(beanFactory)); context.addPropertyAccessor(new BeanExpressionContextAccessor()); Expression expression = parser.parseExpression("someOtherBean.getData()"); BeanExpressionContext rootObject = new BeanExpressionContext(beanFactory, null); ... String value = expression.getValue(context, rootObject, String.class);

Answer 2

请查看@ https://www.mkyong.com/spring3/test-spring-el-with-expressionparser/

示例java代码

import org.springframework.expression.Expression;
import org.springframework.expression.ExpressionParser;
import org.springframework.expression.spel.standard.SpelExpressionParser;
import org.springframework.expression.spel.support.StandardEvaluationContext;

public class App {
    public static void main(String[] args) {

        ExpressionParser parser = new SpelExpressionParser();

        //literal expressions
        Expression exp = parser.parseExpression("'Hello World'");
        String msg1 = exp.getValue(String.class);
        System.out.println(msg1);

        //method invocation
        Expression exp2 = parser.parseExpression("'Hello World'.length()");
        int msg2 = (Integer) exp2.getValue();
        System.out.println(msg2);

        //Mathematical operators
        Expression exp3 = parser.parseExpression("100 * 2");
        int msg3 = (Integer) exp3.getValue();
        System.out.println(msg3);

        //create an item object
        Item item = new Item("mkyong", 100);
        //test EL with item object
        StandardEvaluationContext itemContext = new StandardEvaluationContext(item);

        //display the value of item.name property
        Expression exp4 = parser.parseExpression("name");
        String msg4 = exp4.getValue(itemContext, String.class);
        System.out.println(msg4);

        //test if item.name == 'mkyong'
        Expression exp5 = parser.parseExpression("name == 'mkyong'");
        boolean msg5 = exp5.getValue(itemContext, Boolean.class);
        System.out.println(msg5);

    }
}

使用Spring Expression Language以编程方式评估bean表达式

2 个答案: