我从列表的Spring mvc控制器生成了以下json字符串。 如何在jquery中访问holidayName属性。
[{"holidayId":1,"holidayName":"Raksha Bandhan",
"holidayStartDate":"Aug 2, 2012 12:00:00 AM",
"holidayEndDate":"Aug 2, 2012 12:00:00 AM"},
{"holidayId":2,"holidayName":"Independence day",
"holidayStartDate":"Aug 15, 2012 12:00:00 AM",
"holidayEndDate":"Aug 15, 2012 12:00:00 AM"}]
答案 0 :(得分:0)
var data=[
{"holidayId":1,"holidayName":"Raksha Bandhan","holidayStartDate":"Aug 2, 2012 12:00:00 AM","holidayEndDate":"Aug 2, 2012 12:00:00 AM"},
{"holidayId":2,"holidayName":"Independence day","holidayStartDate":"Aug 15, 2012 12:00:00 AM","holidayEndDate":"Aug 15, 2012 12:00:00 AM"}
]
$.each(data,function(index,item){
alert(item.holidayName)
});
答案 1 :(得分:0)
我不熟悉Spring MVC,但是你应该注意观察你正在使用的起始“json字符串”是 字符串 还是 对象 。
如果是字符串,则需要首先使用$ .parseJSON作为@Felix提及。
如果它已经是一个对象,那么你可以像@Shyju那样直接访问它,或者像没有每个循环那样访问它:
var input =
[
{
"holidayId": 1,
"holidayName": "Raksha Bandhan",
"holidayStartDate": "Aug 2, 2012 12:00:00 AM",
"holidayEndDate": "Aug 2, 2012 12:00:00 AM"
},
{
"holidayId": 2,
"holidayName": "Independence day",
"holidayStartDate": "Aug 15, 2012 12:00:00 AM",
"holidayEndDate": "Aug 15, 2012 12:00:00 AM"
}
];
console.log(input[0]['holidayName']); //'Raksha Bandhan'
console.log(input[1]['holidayName']); //'Independence Day'
http://jsfiddle.net/zTeX2/