Question

我试图在主窗体的右上角打开一个（非装饰的）子窗体，无论主窗体是最大化还是正常大小。但无论我如何尝试，我都不会把它打开到我想要的地方。

我发现了一篇帖子，描述了如何相对于表单中的另一个控件打开表单，但这也不起作用：

How to display a Modal form in a position relative to the a control in the parent window (opener)

现在尝试在Google上搜索几个小时以获得解决方案，但要么没有答案（双倍）或者我没有搜索紧密的单词组合（更有可能）。

有人可以请我指出类似的问题，或者帮助我如何实现我所希望的目标？

Answer 1

听起来我应该使用你锚定到顶部和右边的UserControl。但是让我们做一个表格。您需要连接其Load事件，以便在重新调整自身后将其移动到正确的位置。然后，您需要主窗体的LocationChanged和Resize事件，以便您可以将子窗体保留在正确的位置。

因此，带有样板Form1和Form2名称的示例程序以及Form1上显示子项的按钮可能如下所示：

public partial class Form1 : Form {
    public Form1() {
        InitializeComponent();
        this.button1.Click += button1_Click;
        this.Resize += this.Form1_Resize;
        this.LocationChanged += this.Form1_LocationChanged;

    }

    Form child;

    private void button1_Click(object sender, EventArgs e) {
        if (child != null) return;
        child = new Form2();
        child.FormClosed += child_FormClosed;
        child.Load += child_Load;
        child.Show(this);
    }

    void child_FormClosed(object sender, FormClosedEventArgs e) {
        child.FormClosed -= child_FormClosed;
        child.Load -= child_Load;
        child = null;
    }

    void child_Load(object sender, EventArgs e) {
        moveChild();
    }

    void moveChild() {
        child.Location = this.PointToScreen(new Point(this.ClientSize.Width - child.Width, 0));
    }

    private void Form1_Resize(object sender, EventArgs e) {
        if (child != null) moveChild();
    }

    private void Form1_LocationChanged(object sender, EventArgs e) {
        if (child != null) moveChild();
    }

}

Answer 2

尝试类似的东西：

 private void button1_Click(object sender, EventArgs e)
        {
            ChildForm win = new ChildForm();
            int screenHeight = Screen.PrimaryScreen.WorkingArea.Height;
            int screenWidth = Screen.PrimaryScreen.WorkingArea.Width;

            Point parentPoint = this.Location;

            int parentHeight = this.Height;
            int parentWidth = this.Width;

            int childHeight = win.Height;
            int childWidth = win.Width;

            int resultX = 0;
            int resultY = 0;

            if ((parentPoint.X + parentWidth + childWidth) > screenWidth)
            {
                resultY = parentPoint.Y;
                resultX = parentPoint.X - childWidth;
            }
            else
            {
                resultY = parentPoint.Y;
                resultX = parentPoint.X + parentWidth;
            }

            win.StartPosition = FormStartPosition.Manual;                   
            win.Location = new Point(resultX, resultY);  
            win.Show();
        }

Answer 3

我认为你应该尝试这样的事情：

private void buttonOpen_Click(object sender, EventArgs e)
{
    Form2 frm2 = new Form2();
    frm2.Show();
    //"this" is the parent form
    frm2.DesktopLocation = new Point(this.DesktopLocation.X + this.Width - frm2.Width, this.DesktopLocation.Y);
}

简单，简单，有效（对我而言）。

在主窗体的右上角打开子窗体

3 个答案: