当我做出这个选择它显示结果所有“车辙”与它的电话号码,我的问题 是每个“车辙”有近10个电话号码,我只需要3个电话号码 每个“车辙”,我尝试使用TOP,但只显示所有表的前3行而不是 第一行是“rut”,我如何才能将TOP仅用于行“rut”而不是全部 表
Select Distinct
t1.rut_cliente as rut_cliente,
t1.nro_fono as numero
--Into #tmp_numeros
From dat_clientes_sucursales_contactos_telefonos t1,dat_rut_clientes t2
where t1.rut_cliente = t2.rut_cliente
and cod_prioridad = 1
这是我对此查询的结果:
Rut_cliente Nro_fono
60506000-5 2046840
60506000-5 3507935
60506000-5 4106886
60506000-5 5440000
60506000-5 5445000
81698900-0 2373281
81698900-0 3541342
81698900-0 3541438
81698900-0 3541518
81698900-0 3542101
这就是我想要的:
Rut_cliente Nro_fono
60506000-5 2046840
60506000-5 3507935
60506000-5 4106886
81698900-0 2373281
81698900-0 3541342
81698900-0 3541438
提前感谢。
答案 0 :(得分:7)
该问题最初标记为SQL Server 2008,您可以使用公用表表达式执行此操作:
;WITH x AS
(
SELECT Rut_cliente, Nro_fono, rn = ROW_NUMBER()
OVER (PARTITION BY Rut_cliente ORDER BY Nro_fono)
FROM dbo.dat_clientes_sucursales_contactos_telefonos AS t1
INNER JOIN dbo.dat_rut_clientes AS t2
ON t1.rut_cliente = t2.rut_cliente
WHERE cod_prioridad = 1
)
SELECT Rut_cliente, Nro_fono FROM x
WHERE rn <= 3
ORDER BY Rut_cliente, Nro_fono;
其他评论:
table, table
语法。使用正确的INNER JOIN
。我explain why here。但是现在我们知道用户实际上正在使用SQL Server 2000.我认为这就是我在那里做的方式,但性能会变得非常糟糕。我不是100%肯定这是有效的(因为我再次猜测哪些列来自哪个表)。
SELECT x.rut_cliente, x.nro_fono, COUNT(*) FROM
(
SELECT t1.rut_cliente, t1.nro_fono
FROM dat_clientes_sucursales_contactos_telefonos AS t1
INNER JOIN dat_rut_clientes AS t2
ON t1.rut_cliente = t2.rut_cliente
WHERE cod_prioridad = 1
) AS x
INNER JOIN dat_clientes_sucursales_contactos_telefonos AS b
ON b.rut_cliente = x.rut_cliente
AND b.nro_fono <= x.nro_fono
GROUP BY x.rut_cliente, x.nro_fono
HAVING COUNT(*) <= 3
ORDER BY x.rut_cliente, x.Nro_fono;
答案 1 :(得分:5)
例如,ROW_NUMBER
是一个窗函数,并返回由group by
确定的每个分区的行号(类似于order by
)。:
WITH CTE AS(
SELECT t1.rut_cliente as rut_cliente, t1.nro_fono as numero,
RN = ROW_NUMBER()OVER(PARTITION BY Rut_cliente ORDER BY Nro_fono)
FROM dbo.dat_clientes_sucursales_contactos_telefonos AS t1
INNER JOIN dbo.dat_rut_clientes AS t2 ON t1.rut_cliente = t2.rut_cliente
WHERE cod_prioridad = 1
)
SELECT rut_cliente as rut_cliente, nro_fono as numero
FROM CTE
WHERE RN <= 3
答案 2 :(得分:0)
试试这个
;with CTE AS (
select Rut_cliente, Nro_fono , ROW_NUMBER() OVER
(PARTITION BY Rut_cliente ORDER BY Nro_fono) rn
FROM dbo.dat_clientes_sucursales_contactos_telefonos AS a
INNER JOIN dbo.dat_rut_clientes AS b
ON a.rut_cliente = b.rut_cliente
WHERE cod_prioridad = 1
)
SELECT * FROM CTE where rn <=3