我在这里遇到了问题。
现在我有三张桌子(宠物,地址,联系方式):
USER TABLE COLUMNS:
PET_ID_PK
PETNAME
ADDRESS_ID_FK
CONTACT_ID_FK
GENDER
OWNER_ID
BOUGHT_DATE
ADDRESS TABLE COLUMNS:
ADDRESS_ID_PK
ADDRESS_STRING
CONTACT TABLE COLUMNS:
CONTACT_ID_PK
CONTACT_NUMBER
我想将这些表连接到一个包含列的表中:
PET_ID_PK
PETNAME
ADDRESS_STRING
CONTACT_NUMBER
GENDER
我希望得到属于特定OWNER_ID的宠物,并按照GENDER(先是FEMALE,然后是MALE)的顺序显示行。在这种情况下,我可以使用ORDER BY CASE。
但是在每个用户表条目中,ADDRESS_ID_FK或CONTACT_ID_FK将是NULL值。 因此,参考Unioning Two Tables With Different Number Of Columns中提供的解决具有NULL值的列的解决方案,我提出了查询:
SELECT DISTINCT ON (pets.pet_id_pk) * FROM
((SELECT pet_id_pk, petname, address_string, NULL AS contact_id_fk, gender
FROM user JOIN address ON address.address_id_pk=address_id_fk)
UNION
(SELECT pet_id_pk, petname, NULL AS address_string, contact_id_fk, gender
FROM user JOIN address ON contact.contact_id_pk=contact_id_fk) AS pets
WHERE OWNER_ID=$1 ORDER BY (CASE WHEN gender=female ELSE 2 END), bought_date DESC
但是此查询无法正常工作。
希望有人可以帮我解决这个问题。谢谢。
答案 0 :(得分:1)
请尝试以下:
SELECT u.pet_id_pk, u.petname, a.address_string, c.contact_number, u.gender
FROM user u
LEFT JOIN address a ON u.address_id_fk=a.address_id_pk
LEFT JOIN contact c ON u.contact_id_fk=c.contact_id_pk
WHERE OWNER_ID=$1 ORDER BY u.gender,bought_date DESC
您可以使用LEFT JOIN。即使没有匹配结果,LEFT JOIN也会显示表格。
对于ORDER BY,我实际上并不认为需要使用CASE,因为只使用ORDER BY,它将显示FEMALE跟随MALE。您是否有使用ORDER BY CASE的具体原因?