Question

我正在尝试使用put请求调用url，而url是

PUT https://www.googleapis.com/groups/v1/groups/groupUniqueId但是得到错误响应为{“error”：{“errors”：[{“domain”： “global”，“reason”：“required”，“message”：“Required”}]，“code”： 400，“消息”：“必需”}}

如果我打开链接 https://developers.google.com/google-apps/groups-settings/v1/reference/groups/update 然后有一个Try It Section我用OAuth2.0授权它并放置一些字段，如图像 enter image description here

我编写了一个用于调用此url的java servlet 这是它的doGet方法代码，我正在Google Appengine.i上编写它，授权使用oauth2和acess_token的应用程序是有效的，否则它将显示授权错误。它显示了无效的值。

public void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws IOException {

        String url = "https://accounts.google.com/o/oauth2/token";

        // FetchOptions opt = FetchOptions.Builder.doNotValidateCertificate();
           URL url1=new URL(url); 
           String param="code="+req.getParameter("code")+"&client_id=719226850877-tr21kp47phthuli0hu2v24akgfrplde9.apps.googleusercontent.com&client_secret=hSXi3dWfEmDQfl0XZJJmBssc&redirect_uri=https://www.onemoredemo.appspot.com/oauth2callback&grant_type=authorization_code";

             HttpURLConnection connection = 
        (HttpURLConnection)url1.openConnection(); 
             connection.setDoOutput(true); 
             connection.setRequestMethod("POST"); 
             connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded");
             connection.getOutputStream().write( param.getBytes() ); 
          InputStream str= connection.getInputStream();
          BufferedReader reader=new BufferedReader(new InputStreamReader(str));
        String l="";
        String l1="";

          while((l=reader.readLine())!=null){
              l1+=l;
             resp.getWriter().println(l);

          }
          try {
              JSONObject obj=new JSONObject();
              obj.put("email", "testing9@iritesh.com");
            JSONObject json=new JSONObject(l1);
            String access_token=json.getString("access_token");
            URL url2=new URL("https://www.googleapis.com/groups/v1/groups/testing@iritesh.com?key=AIzaSyATDZHO5J7a3ItTSBhPby__Xzxi7rZlMJQ");
            HttpURLConnection connection1=(HttpURLConnection) url2.openConnection();
            connection1.setRequestMethod("PUT");
            connection1.addRequestProperty("Content-Type", "application/json");
            connection1.setDoOutput(true);
            connection1.addRequestProperty("Authorization","Bearer "+ access_token);
            connection1.getOutputStream().write(obj.toString().getBytes());
            connection1.connect();
            InputStream str1= connection1.getInputStream();
              BufferedReader reader1=new BufferedReader(new InputStreamReader(str1));
             String rit;
              while( (rit=reader1.readLine())!=null)
             {resp.getWriter().println(rit);

             }


        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


    }

我试图提出与图片相同的请求。首先将关键参数设置为api key，然后通过调用setRequestMethod（“PUT”）将请求方法设置为PUT; 之后添加了两个属性，一个是Authorization：Bearer access_token 然后是Content-Type：application / json 然后通过调用方法

将其请求体设置为json对象

connection1.getOutputStream().write(obj.toString().getBytes());

任何人都可以指出我错在哪里以及我的价值无效吗？

Answer 1

因为我正在尝试更改群组的电子邮件地址，但是当我在群组页面中手动尝试时，它无法更改，这就是我收到400错误的原因

Google Apps应用程序组设置API中的错误400无效值

1 个答案: