Question

我有以下代码：

    class Animal
        constructor: (@name) -> 
        say: () -> console.log "Hello from animal called #{ @name }"

    class Dog extends Animal

        say: () ->
            super.say()
            console.log "Hello from dog called #{ @name }"

    a = new Animal('Bobby')
    a.say()

    d = new Dog("Duffy")
    d.say()

结果不是

Hello from animal called Bobby
Hello from animal called Duffy
Hello from dog called Duffy

但是我收到以下错误：

Hello from animal called Bobby
Hello from animal called Duffy
Uncaught TypeError: Cannot call method 'say' of undefined

为什么超级未定义？如何调用父方法以扩展它？感谢

Answer 1

我自己找到了答案，应该是：

class Dog extends Animal

    say: () ->
        super
        console.log "Hello from dog called #{ @name }"

调用coffeescript超级方法

1 个答案: