Question

我需要播放不同音频输出的音乐。例如，我有两个音乐：music1和music2，并且他们必须在不同的扬声器中分开播放。假设我有多个音频设备可以使用播放声音：

我找到了这个方法（here - 它是BasicPlayer）：

protected void createLine() throws LineUnavailableException
{
    log.info("Create Line");
    if (m_line == null)
    {
        AudioFormat sourceFormat = m_audioInputStream.getFormat();
        log.info("Create Line : Source format : " + sourceFormat.toString());
        int nSampleSizeInBits = sourceFormat.getSampleSizeInBits();
        if (nSampleSizeInBits <= 0) nSampleSizeInBits = 16;
        if ((sourceFormat.getEncoding() == AudioFormat.Encoding.ULAW) || (sourceFormat.getEncoding() == AudioFormat.Encoding.ALAW)) nSampleSizeInBits = 16;
        if (nSampleSizeInBits != 8) nSampleSizeInBits = 16;
        AudioFormat targetFormat = new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, sourceFormat.getSampleRate(), nSampleSizeInBits, sourceFormat.getChannels(), sourceFormat.getChannels() * (nSampleSizeInBits / 8), sourceFormat.getSampleRate(), false);
        log.info("Create Line : Target format: " + targetFormat);
        // Keep a reference on encoded stream to progress notification.
        m_encodedaudioInputStream = m_audioInputStream;
        try
        {
            // Get total length in bytes of the encoded stream.
            encodedLength = m_encodedaudioInputStream.available();
        }
        catch (IOException e)
        {
            log.error("Cannot get m_encodedaudioInputStream.available()", e);
        }
        // Create decoded stream.
        m_audioInputStream = AudioSystem.getAudioInputStream(targetFormat, m_audioInputStream);
        AudioFormat audioFormat = m_audioInputStream.getFormat();
        DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat, AudioSystem.NOT_SPECIFIED);
        Mixer mixer = getMixer(m_mixerName);
        if (mixer != null)
        {
            log.info("Mixer : "+mixer.getMixerInfo().toString());
            m_line = (SourceDataLine) mixer.getLine(info);
        }
        else 
        {
            m_line = (SourceDataLine) AudioSystem.getLine(info);
            m_mixerName = null;
        }
        log.info("Line : " + m_line.toString());
        log.debug("Line Info : " + m_line.getLineInfo().toString());
        log.debug("Line AudioFormat: " + m_line.getFormat().toString());
    }
}

通过一些调试，我发现调音台始终为空。这是为什么？调音台不是通过目标线输出声音的设备吗？此程序始终在我的计算机上设置的默认设备中播放，我该怎么做才能更改它？

Answer 1

我实际上刚开始使用Java Sound API来完成我自己的一个项目，但据我所知，Mixer只是一个接口，而不是一个对象。这可以解释你问题的一部分。

在多个输出中播放音频

1 个答案: