Question

如何在xpath中获取以下信息？

文字01 - link_1.com

文字02 - link_2.com

$page = '
<div class="news">
<div class="content">
    <div>
    <span class="title">Text 01</span>
    <span class="link">link_1.com</span>
    </div>
</div>
<div class="content">
    <div>
    <span class="title">Text 02</span>
    <span class="link">link_2.com</span>
    </div>
</div>
</div>';
@$this->dom->loadHTML($page);
$xpath = new DOMXPath($this->dom);

// perform step #1
$childElements = $xpath->query("//*[@class='content']");
$lista = '';
foreach ($childElements as $child) {
    // perform step #2
    $textChildren = $xpath->query("//*[@class='title']", $child);
    foreach ($textChildren as $n) {
        echo $n->nodeValue.'<br>';
    }

    $linkChildren = $xpath->query("//*[@class='link']", $child);
    foreach ($linkChildren as $n) {
        echo $n->nodeValue.'<br>';
    }
}

我的结果是返回

文字01

文字02

link_1.com

link_2.com

文字01

文字02

link_1.com

link_2.com

Answer 1

在第二个和第三个xpath中将//替换为descendant::，因为//告诉xpath在xml中搜索此元素evrywhere而不是在特定节点中（根据需要）和$ child不是单独的XML。 descendat::表示任何子节点

@$this->dom->loadHTML($page);
$xpath = new DOMXPath($this->dom);

// perform step #1
$childElements = $xpath->query("//*[@class='content']");
$lista = '';
foreach ($childElements as $child) {
    // perform step #2
    $textChildren = $xpath->query("descendant::*[@class='title']", $child);
    foreach ($textChildren as $n) {
        echo $n->nodeValue.'<br>';
    }

    $linkChildren = $xpath->query("descendant::*[@class='link']", $child);
    foreach ($linkChildren as $n) {
        echo $n->nodeValue.'<br>';
    }
}

Php Xpath - 如何在子节点中获取两个信息

1 个答案: