我将日期作为字符串格式为:
2010-12-31 20:21:00 +0200
我想要做的是使用NSDateFormatter将其解析为NSDate对象,但我无法正确匹配格式。
NSDateFormatter *dateFormatter = NSDateFormatter.alloc.init;
[dateFormatter setTimeZone: NSTimeZone.localTimeZone];
[dateFormatter setDateFormat: @"yyyy-MM-dd HH:mm:ss'Z'"];
[dateFormatter dateFromString: @"2010-12-31 20:21:00 +0200"] // returns nil ;
有人能帮我找到正确的格式吗?谢谢
答案 0 :(得分:3)
此代码有效:
NSDateFormatter *dateFormatter = NSDateFormatter.alloc.init;
[dateFormatter setTimeZone:NSTimeZone.localTimeZone];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss Z"];
NSDate *date = [dateFormatter dateFromString:@"2010-12-31 20:21:00 +0200"];
NSLog(@"%@", [dateFormatter stringFromDate:date]);
我只是想让你知道,亲切的先生,当我看到NSDateFormatter.alloc.init
答案 1 :(得分:0)
NSDateFormatter* format = [[NSDateFormatter alloc]init];
[format setDateFormat:@"MM/dd/YYYY"];
NSString * currentDate = [format stringFromDate:[NSDate date]];
NSDate *date = [format dateFromString:currentDate];