Question

我使用以下代码接收邮件而不删除。现在我需要添加一些过滤并删除一些消息。我的问题是如何在其他消息留在队列中时删除特定消息？

    Uri connecturi = new Uri("activemq:tcp://model.net:61616");
    IConnectionFactory factory = new NMSConnectionFactory(connecturi);
    List<ModelBuilderBase> result = new List<ModelBuilderBase>();
    using (IConnection connection = factory.CreateConnection())
    using (ISession session = connection.CreateSession())
    {

        IDestination destination = SessionUtil.GetDestination(session, "queue://cidModelbuilderQ");
        using (IMessageConsumer consumer = session.CreateConsumer(destination))
        {
            connection.Start();
            var q = session.GetQueue("cidModelbuilderQ");
            var b = session.CreateBrowser(q);
            var msgs = b.GetEnumerator();
            while (msgs.MoveNext())
            {
                ITextMessage message = msgs.Current as ITextMessage;
                if (message.Properties[MANDATOR] == null || message.Properties[REFCODE] == null)
                    continue;
                var mandator = message.Properties[MANDATOR].ToString();
                var refCode = message.Properties[REFCODE].ToString();
                result.Add(ModelBuilderFactory.Instance.GetInstance(refCode, mandator));
            }
        }
    }

Answer 1

使用选择器并获取这些消息。

创建消费者时，按创建它 IMessageConsumer consumer = session.CreateConsumer（destination，“REFCODE＆gt; 200”）或类似的，取决于你需要寻找什么。然后只需调用consumer.receive（timeout_val）;直到你拉出队列的所有选定消息。 Info about AMQ selectors

ActiveMQ删除特定消息

1 个答案: