Question

我的表：

id attribute
1  2
1  2
2  3
2  4
5  1
5  1
6  3
6  3
6  5

现在我只希望用id输出attribute，如果每个id的属性相同。

在此示例表中，输出为

id attribute
1  2
5  1

Answer 1

SELECT id, MIN(attribute) AS attribute 
FROM test  
GROUP BY id
HAVING COUNT(DISTINCT attribute) = 1 ;

或：

SELECT id, MIN(attribute) AS attribute
FROM test 
GROUP BY id
HAVING MIN(attribute) = MAX(attribute) ;

我希望最后一个版本在(id, attribute)

的索引上非常有效

Answer 2

你可以使用这种方法：

SELECT DISTINCT id, attribute 
FROM test t1 
WHERE (SELECT count(DISTINCT attribute) 
       FROM test t2 
       WHERE t2.id = t1.id) = 1

更好的方法可能是：

SELECT
   DISTINCT t1.id, t1.attribute
FROM
   test t1,
   (
      SELECT
         id,
         count(DISTINCT attribute) COUNT
      FROM
         test
      GROUP BY
         id
      HAVING
         COUNT = 1
   ) t2
WHERE
   t1.id = t2.id

Answer 3

好吧，我会改用以下方法：

     SELECT DISTINCT ta.id, ta.attribute
       FROM test ta
  LEFT JOIN test tb
         ON ta.id = tb.id AND ta.attribute <> tb.attribute
      WHERE tb.id IS NULL;

...因为我通常倾向于至少尝试用连接表替换嵌套查询。当然，如果你的桌子很小，那就不重要了。

检查列是否有唯一值

3 个答案: