Question

我是php的新手，我正在尝试添加此代码

我发现这个错误请任何能为我解决这个问题的人

<?php
$myName = ‘Guest’;
$myVar = “Welcome back $myName”;
echo $myVar;
?>

这是我的HTML

<p><?php echo $myVar; ?></p>

由于

Answer 1

看起来你使用的是有趣的引号，而不是直接的'和'类型。

<?php
$myName = 'Guest';
$myVar = "Welcome back $myName";
echo $myVar;
?>

Answer 2

你需要写

$myVar = "Welcome Back $myName";

问题是您使用了错误的char作为引用字符

Answer 3

instructionBtn = Button(window, text="?", command=start, height = 5, width  =30,fg="black", bg="lime green", font=("Comic Sans MS", 10))
instructionBtn.grid(row=29, column=1, sticky=S)

window.mainloop()

def instruction():
    instructionwindow = Tk() #create window 
    instructionwindow.geometry("500x350")

    instructionwindow.title("Instruction")
    instructionwindow.configure(background='white')

    instructionFile=open("Instruction.txt","r")
    instruction.read


textboxOutput = Text(window, wrap="Instruction.txt", width = 150, height = 20)
textboxOutput.grid(row = 20, column = 0, columnspan=10)


instruction.mainloop()

或

<?php
    $myName = "Guest";
    $myVar = "Welcome back ".$myName;
    echo $myVar;
?>

这是连接字符串时代码的工作方式。

Answer 4

代替$myVar = “Welcome back" . $myName;

撰写$myVar = “Welcome back $myName";

<?php
$myName = ‘Guest’;
$myVar = “Welcome back" . $myName;
echo $myVar;
?>

解析错误：语法错误，第3行的C：\ xampp \ htdocs \ yo \ index.php中的意外T_STRING

4 个答案: