我正在进行2项活动。一个活动有一个textView和一个按钮。 textView显示了爱好,如果用户点击按钮,将会设置爱好。当用户点击该按钮时,他/她将转到第二个活动,该活动具有与爱好相对应的4个复选框。当用户从菜单中单击“完成”时,他/她将返回到第一个活动,之后,检查的爱好将显示在文本视图中,以逗号(“,”)分隔。我的问题是,当用户再次使用按钮设置爱好但已经在textView中显示爱好时,应根据textView中显示的内容初始化第二个Activity中的复选框。我已经尝试过数组,甚至是硬编码,但我陷入了逻辑上。这是我的代码。假设所有视图都已初始化:
第一屏(重要位):
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == RESULT_OK) {
switch (requestCode) {
case SET_BIRTHDAY:
TextView textBirthday = (TextView) findViewById(R.id.tvBirthdayStat);
birthdayString = data.getStringExtra(Lab2_082588birthday.MONTH)
+ "/" + data.getStringExtra(Lab2_082588birthday.DAY)
+ "/" + data.getStringExtra(Lab2_082588birthday.YEAR);
textBirthday.setText(birthdayString);
break;
case SET_HOBBIES:
TextView textHobbies = (TextView) findViewById(R.id.tvHobbiesStat);
anime = data.getStringExtra(Lab2_082588hobbies.ANIME);
games = data.getStringExtra(Lab2_082588hobbies.GAMES);
movies = data.getStringExtra(Lab2_082588hobbies.MOVIES);
books = data.getStringExtra(Lab2_082588hobbies.BOOKS);
checkNull();
textHobbies.setText(hobbiesString);
break;
}
}
}
private void checkNull() {
// TODO Auto-generated method stub
if (games == null) {
hobbiesString = books + " , " + movies + " , " + anime;
}
if (anime == null) {
hobbiesString = games + " , " + books + " , " + movies;
}
if (movies == null) {
hobbiesString = games + " , " + books + " , " + anime;
}
if (books == null) {
hobbiesString = games + " , " + movies + " , " + anime;
}
if ((games == null) && (anime == null)) {
hobbiesString = books + " , " + movies;
}
if ((games == null) && (movies == null)) {
hobbiesString = books + " , " + anime;
}
if ((games == null) && (books == null)) {
hobbiesString = movies + " , " + anime;
}
if ((anime == null) && (movies == null)) {
hobbiesString = games + " , " + books;
}
if ((anime == null) && (books == null)) {
hobbiesString = games + " , " + movies;
}
if ((movies == null) && (books == null)) {
hobbiesString = games + " , " + anime;
}
if ((movies == null) && (books == null) && (anime == null)) {
hobbiesString = games;
}
if ((movies == null) && (games == null) && (anime == null)) {
hobbiesString = books;
}
if ((games == null) && (books == null) && (anime == null)) {
hobbiesString = movies;
}
if ((movies == null) && (books == null) && (games == null)) {
hobbiesString = anime;
}
}
第二个屏幕:
private void startUp() {
// TODO Auto-generated method stub
Intent startUp = getIntent();
String receivedString = startUp.getStringExtra(HOBBIES_STRING);
if (receivedString != null) {
String[] separated = receivedString.split(",");
if (separated.length > 0) {
if (separated[0].equals("Anime")) {
anime.setChecked(true);
}
/*----------------*/
if (separated[0].equals("Computer Games")) {
games.setChecked(true);
}
/*----------------*/
if (separated[0].equals("Books")) {
books.setChecked(true);
}
/*----------------*/
if (separated[0].equals("Movies")) {
movies.setChecked(true);
}
/*----------------*/
if (separated[0].equals("Anime")&& separated[0].equals("Computer Games")) {
anime.setChecked(true);
games.setChecked(true);
}
if (separated[0].equals("Anime")&&separated[0].equals("Books")) {
anime.setChecked(true);
books.setChecked(true);
}
if (separated[0].equals("Anime")&&separated[0].equals("Movies")) {
anime.setChecked(true);
movies.setChecked(true);
}
}
}
代码仍未按预期运行。正如您所看到的,我使用了字符串拆分和字符串数组,但由于极端硬编码和数组索引边界问题,使用数组使其难以处理。
答案 0 :(得分:2)
对于CheckNull方法,我将使用以下
private void checkNull() {
hobbiesstring = "";
if (games != null)
hobbiesstring += games;
if (anime != null)
hobbiesstring += anime;
if (books != null)
hobbiesstring += books;
if (movies != null)
hobbiesstring += movies;
}
对于第二部分,我将使用以下代码
private void startUp() {
Intent startUp = getIntent();
String receivedString = startUp.getStringExtra(HOBBIES_STRING);
if (receivedString != null) {
String[] separated = receivedString.split(",");
foreach(string sep in seperated){
switch(sep){
case "Anime":
anime.setChecked(true);
break;
case "Movies":
movies.setChecked(true);
break;
case "Books":
books.setChecked(true);
break;
case "Games":
games.setChecked(true);
break;
}
}
}
}
答案 1 :(得分:0)
您可能希望使用Preferences
实现此功能。让您的第二个Activity
成为PreferenceActivity
,并选中复选框CheckBoxPreferences
。当用户选中/取消选中它们时,值会自动保存在SharedPreferences
中。然后,当您返回到第一个Activity
时,您只需使用保存在SharedPreferences
中的布尔值来显示值。您可以在Preferences
和here's 上获取有关SharedPreferences
的精彩帖子的google,这也很有用。希望这会有所帮助。
答案 2 :(得分:0)
您是否尝试将“,
”传递给StringTokenizer?
这不是那么重要,但你可以像这样进行优化
if (games == null) {
hobbiesString = books + " , " + movies + " , " + anime;
if (books == null) {
hobbiesString = movies + " , " + anime;
if (anime == null) {
hobbiesString = movies;
}
}
} else if(books == null) {
...
} else ...