Question

我目前有一个shell脚本，其中一段代码运行远程shell命令，如下所示：

grep -v "^[     ]*#" ${CONFIG_FILE} |
while read SERVER USER LOGDIR
do
{
echo "Stats for" $date
echo "${USER}"
echo "iTunes:"
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"iTunes Music\" ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print \"Total=\" total}'" 2>&1
echo
echo "Default"
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"Default Player\" ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print \"Total=\" total}'" 2>&1
echo
echo "The Rest"
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"Junk\"     ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print \"Total=\" total}'" 2>&1
} </dev/null 2>&1

done 2>${ERROR_FILE} >${STATS_FILE}

这给了我这样的输出：

Stats for 20120628
Rich
iTunes:
Total=0

real 0m2.09s
user 0m0.22s
sys  0m0.03s

Default:
Total=0

real 0m2.03s
user 0m0.23s
sys 0m0.00s

The Rest:
Total=0

real 0m2.03s
user 0m0.23s
sys 0m0.00s

Stats for 20120628
Ian
iTunes:
Total=2

real 0m21.44s
user 0m0.22s
sys 0m0.00s

Default:
Total=2

real 0m21.48s
user 0m0.21s
sys 0m0.02s

The Rest:
Total=0

real 0m2.03s
user 0m0.23s
sys 0m0.00s

等等......

我想要的是以CSV格式输出：

Rich,0,0,0
Ian,2,2,0

修改上述代码以获取我需要的输出格式的最简单方法是什么？

谢谢！

Answer 1

grep -v "^[     ]*#" ${CONFIG_FILE} |
while read SERVER USER LOGDIR
do
{
echo "${USER},"
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"iTunes Music\" ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print total \",\"}'" 2>&1
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"Default Player\" ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print total \",\"}'" 2>&1
time /bob/shared/ted/remote/rssh ${SERVER} "gzgrep -c \"Junk\"     ${LOGDIR}/*${date}*.gz | awk '-F:' '{total+=\$NF}END{print total}'" 2>&1
} </dev/null 2>&1 | tr -d '\n'

done 2>${ERROR_FILE} >${STATS_FILE}

我删除了额外的echo，附加了逗号并确保它在一行上。试试吧。

如果您不想要时间信息，只需删除所有time次调用。

远程shell，将脚本输出更改为csv

1 个答案: