使用Xaml和WPF,如何在单击时为属性设置动画,然后在连续单击时反转

时间:2009-07-14 16:18:09

标签: wpf animation properties double

我想知道是否有办法只使用XAML在属性上执行动画,然后在下一次单击时执行反向动画?

以下是我在Border对象上的Trigger示例,它给出了滑出的外观:

<!-- Animates the Width to Slide It Out. -->
<EventTrigger RoutedEvent="Border.MouseLeftButtonUp">
  <BeginStoryboard>
     <Storyboard>
        <DoubleAnimation Storyboard.TargetName="theFilterControl"
             Storyboard.TargetProperty="Width"
             From="16"
             To="170"
             Duration="0:0:.7" />
      </Storyboard>
    </BeginStoryboard>
 </EventTrigger>

2 个答案:

答案 0 :(得分:3)

您可以为ToggleButton创建一个ControlTemplate并在其中添加边框。而Button ControlTemplate可以为动画提供IsPressed属性。

<ToggleButton>
    <ToggleButton.Template>
        <ControlTemplate  TargetType="{x:Type ToggleButton}">
            <Border x:Name="theFilterControl" Background="#FF686868" 
                BorderBrush="Black" Width="16" />
            <ControlTemplate.Triggers>
                <EventTrigger RoutedEvent="ToggleButton.Checked">
                    <BeginStoryboard> 
                    <Storyboard>
                          <DoubleAnimation Storyboard.TargetName="theFilterControl"
                                 Storyboard.TargetProperty="Width"
                                 From="16"
                                 To="170"
                                 Duration="0:0:.7" />
                    </Storyboard>
                    </BeginStoryboard>
                </EventTrigger>
                <EventTrigger RoutedEvent="ToggleButton.Unchecked">
                    <BeginStoryboard>
                        <Storyboard>
                          <DoubleAnimation Storyboard.TargetName="theFilterControl"
                                 Storyboard.TargetProperty="Width"
                                 From="170"
                                 To="16"
                                 Duration="0:0:.7" />
                          </Storyboard>
                    </BeginStoryboard>
                </EventTrigger>
            </ControlTemplate.Triggers>
        </ControlTemplate>
    </ToggleButton.Template>
</ToggleButton>

答案 1 :(得分:2)

来自Jobi的ToggleButton的好主意,谢谢!您也可以通过在ControlTemplate外部和UserControl(或Page)触发器区域内定义ToggleButton的触发器来解决范围问题,例如。

  <UserControl.Triggers>
    <EventTrigger RoutedEvent="ToggleButton.Checked"
                  SourceName="ExpandCollapseToggleButton">
        <EventTrigger.Actions>
            <BeginStoryboard>
                <Storyboard>
                    <DoubleAnimation 
                        Storyboard.TargetName="SidebarCanvas"
                        Storyboard.TargetProperty="Width"
                        To="0"
                        Duration="0:0:0.15" />
                </Storyboard>
            </BeginStoryboard>
        </EventTrigger.Actions>
    </EventTrigger>
    <EventTrigger RoutedEvent="ToggleButton.Unchecked"
                  SourceName="ExpandCollapseToggleButton">
        <EventTrigger.Actions>
            <BeginStoryboard>
                <Storyboard>
                    <DoubleAnimation 
                        Storyboard.TargetName="SidebarCanvas"
                        Storyboard.TargetProperty="Width"
                        To="250"
                        Duration="0:0:0.15" />
                </Storyboard>
            </BeginStoryboard>
        </EventTrigger.Actions>
    </EventTrigger>
</UserControl.Triggers>

ControlTemplate的范围似乎与UserControl / Page完全不同,因此您无法在这些范围之间引用目标。