Question

所以我想把我的代码变成JSON是以下

var locationData = [];
locationData['lat'] = position.coords.latitude;
locationData['long'] = position.coords.longitude;
locationData['address']['road'] = data['address']['road'];
locationData['address']['suburb'] = data['address']['suburb'];
locationData['address']['city'] = data['address']['city'];
locationData['address']['county'] = data['address']['county'];
locationData['address']['state'] = data['address']['state'];
locationData['address']['postcode'] = data['address']['postcode'];
locationData['address']['country'] = data['address']['country'];
locationData['address']['country_code'] = data['address']['country_code'];

但是当我运行它时，它并没有提醒我它已经成功

Answer 1

您的初始声明是错误的：

var locationData = [];

创建一个数组，它不会像你期望的那样工作;你想要一个对象。您还需要初始化内部的任何复杂数据结构，例如address：

var locationData = {
    address: {}
}

<强>旁注

数组也是JavaScript中的对象，但在使用数字属性时，它以特殊方式运行。在您的情况下，您根本不使用数字属性，这就是常规对象更适合您需求的原因。

Answer 2

正如您将locationData声明为数组一样，您还需要将locationData ['address']声明为数组。（locationData['address']=[]在你的第三或第四行。）

jQuery不会把这变成JSON

2 个答案: