可能重复:
JSON Parsing in Android
我发现我需要使用Gson类将json解析为android中的Java对象。解析简单的变量或数组很容易,但我不知道如何解析更复杂的json字符串,我的json看起来像这样:
{"selected_id":3, "data":[{"id":"3","score":"1534"},{"id":"1","score":"1234"}]}
任何人都可以帮我解决这个问题吗?
答案 0 :(得分:1)
//Model class
class Model {
private String mId ;
private String mScore;
public Model (String id , String score){
mId = id ;
mScore= score
}
//getter and setter
}
//在你的班级
private ArrayLsit getLsit(String str){
ArrayLsit<Model > list = new ArrayLsit<Model>();
// getting JSON string from URL
JSONObject json = new JSONObject(str);
try {
// Getting Array of Contacts
contacts = json.getJSONArray("data");
// looping through All Contacts
for(int i = 0; i < contacts.length(); i++){
JSONObject c = contacts.getJSONObject(i);
// Storing each json item in variable
String id = c.getString("id");
String score= c.getString("score");
list.add(new Model(id ,score))
}
} catch (JSONException e) {
e.printStackTrace();
}
return list
}
答案 1 :(得分:0)
查看代码..
Result = jsonObject.getString("data");
jsonArray = new JSONArray(Result);
for (int i = 0; i < jsonArray.length(); i++) {
jsonObject = jsonArray.getJSONObject(i);
try {
jsonObject.getString("Id");
} catch (Exception ex) {
cafeandbarsList.add(null);
ex.printStackTrace();
}
}
由于
答案 2 :(得分:0)
为json创建类,
Gson gson = new Gson(); Jsondata jsonddata = gson.fromJson(response,Jsondata .class);
===== JsonData.jave
@SerializedName("selected_id")
public String sid;
@SerializedName("data")
public List<data> dalalist;
=== data.java
@SerializedName("id")
public String id;
@SerializedName("score")
public String score;