Question

我收到错误“_reverse_with_prefix（）参数在*必须是序列之后，而不是int”当我尝试反转时。我以前在视图中硬编码参数，但我试图使其动态化。有什么建议吗？

查看：

def add_review(request, product_id):
    p = get_object_or_404(Product, pk=product_id)
    if request.method == 'POST':
        form = ReviewForm(request.POST)
        if form.is_valid():
            form.save()
            #HARDCODED: return HttpResponseRedirect('/products/1/reviews/')
            return HttpResponseRedirect(reverse('view_reviews', args=(p.id)))
    else:
        form = ReviewForm()
    variables = RequestContext(request, {'form': form})
    return render_to_response('reserve/templates/create_review.html', variables)        


def view_reviews(request, product_id):
    product = get_object_or_404(Product, pk=product_id)
    reviews = Review.objects.filter(product_id=product_id)
    return render_to_response('reserve/templates/view_reviews.html', {'product':product, 'reviews':reviews},
    context_instance=RequestContext(request))


urlpatterns = patterns('reserve.views',
    url(r'^clubs/$', 'index'),
    url(r'^products/(?P<product_id>\d+)/reviews/$', 'view_reviews'),
    url(r'^products/(?P<product_id>\d+)/add_review/$', 'add_review'),
    url(r'^admin/', include(admin.site.urls)),
)

Answer 1

检查args=(p.id)内的reverse()，必须是args=(p.id,)。第一种形式被视为整数而不是序列。

参考the doc和the tutorial：

一个特殊问题是构造包含0或1的元组 items：语法有一些额外的怪癖来容纳这些。空元组是由一对空括号构成的;一个元组通过使用逗号跟随值来构造一个项目（它不是足以将一个值括在括号中。）

另外，请使用'reserve.views.view_reviews'而不仅仅是'view_reviews'，因此：

reverse('reserve.views.view_reviews', args=(p.id,))

检查the doc of reverse

Answer 2

由于您的模式为变量指定了匹配项，因此它被视为关键字参数，因此您应该将调用调整为反向。

return HttpResponseRedirect(reverse('view_reviews', kwargs={'product_id':p.id})

Answer 3

那是因为args需要元组，但是当你使用args =（p.id）时，实际上，python会认为是整数p.id，你可以看看源代码django 1.6如下：

def reverse(viewname, urlconf=None, args=None, kwargs=None, prefix=None, current_app=None):
if urlconf is None:
    urlconf = get_urlconf()
resolver = get_resolver(urlconf)
args = args or []
kwargs = kwargs or {}
if prefix is None:
    prefix = get_script_prefix()
if not isinstance(viewname, six.string_types):
    view = viewname
else:
    parts = viewname.split(':')
    parts.reverse()
    view = parts[0]
    path = parts[1:]
    resolved_path = []
    ns_pattern = ''
    while path:
        ns = path.pop()

        # Lookup the name to see if it could be an app identifier
        try:
            app_list = resolver.app_dict[ns]
            # Yes! Path part matches an app in the current Resolver
            if current_app and current_app in app_list:
                # If we are reversing for a particular app,
                # use that namespace
                ns = current_app
            elif ns not in app_list:
                # The name isn't shared by one of the instances
                # (i.e., the default) so just pick the first instance
                # as the default.
                ns = app_list[0]
        except KeyError:
            pass

        try:
            extra, resolver = resolver.namespace_dict[ns]
            resolved_path.append(ns)
            ns_pattern = ns_pattern + extra
        except KeyError as key:
            if resolved_path:
                raise NoReverseMatch(
                    "%s is not a registered namespace inside '%s'" %
                    (key, ':'.join(resolved_path)))
            else:
                raise NoReverseMatch("%s is not a registered namespace" %
                                     key)
    if ns_pattern:
        resolver = get_ns_resolver(ns_pattern, resolver)

return iri_to_uri(resolver._reverse_with_prefix(view, prefix, *args, **kwargs))

看看这个iri_to_uri（resolver._reverse_with_prefix（view，prefix，* args，** kwargs）），它使用* args，所以你应该确保args是一个序列，

根据文档，带有一个项目的元组应该添加逗号来创建，你的代码应该是这样的：

return HttpResponseRedirect(reverse('view_reviews', args=(p.id,)))

如何用反向正确地做HttpResponseRedirect？

3 个答案: