Question

我正在使用django-relationships，我正在通过以下关注者数量过滤我的用户：

Relationship.objects.values('to_user').annotate(num_followers=Count('to_user')).order_by('-num_followers')

返回类似这样的内容

[{'to_user': 1, 'num_followers': 3}, {'to_user': 4, 'num_followers': 1}]

我的问题是我需要访问我的User对象，而不仅仅是pk。现在我正在做这样的事情：

tu_list = []
for tu in top_users_set:
    tu_list.append({
        'top_user': User.objects.get(pk=tu['to_user']),
        'followers': tu['num_followers'],
    })

正在为每个用户进行查询。由于查询集可能最终拥有数百个+用户，因此这可能非常糟糕。

任何有助于改善这一点的输入都将受到赞赏。

由于

Answer 1

如果您想要用户，则需要通过查询用户模型和加入关系来反过来访问它。这是相关的documentation

应该是这样的：

from django.db.models import Count

users = User.objects.annotate(num_followers=Count('to_users')).order_by('-num_followers')

这会为您提供用户，并且每个人都会有一个额外的属性 num_followers

model.py

from django.contrib.auth.models import User
from django.db import models

class Relationship(models.Model):
    from_user = models.ForeignKey(User, related_name='from_users')
    to_user = models.ForeignKey(User, related_name='to_users')

测试

>>> from so.models import *
>>> from django.contrib.auth.models import User
>>> u1 = User()
>>> u1.username='user1'
>>> u1.save()
>>> u2 = User()
>>> u2.username='user2'
>>> u2.save()
>>> u3=User()
>>> u3.username='user3'
>>> u3.save()
>>> # so we have 3 users now
>>> r1 = Relationship()
>>> r1.from_user=u1
>>> r1.to_user=u2
>>> r1.save()
>>> r2=Relationship()
>>> r2.from_user=u1
>>> r2.to_user=u3
>>> r2.save()
>>> r3=Relationship()
>>> r3.from_user=u2
>>> r3.to_user=u3
>>> r3.save()
>>> rels = Relationship.objects.all()
>>> rels.count()
3
>>> # we have 3 relationships: user1 follows user2, user1 follows user3, user2 follows user3
>>> users = User.objects.annotate(num_followers=Count('to_users')).order_by('-num_followers')
>>> for user in users:
>>>     print user.username, user.num_followers
user3 2
user2 1
user1 0

EDIT2 修正了拼写错误，添加了测试

Django - 在带注释的查询中访问外键数据

1 个答案: