我的缓存设置为TRUE,我的缓存文件夹现在甚至设置为777。
但是当我查看图像路径时,它仍然显示原始文件的文件名和路径?
它不应该向我展示缓存图像的路径吗?
Timthumb设置:
define ('CACHE_SIZE', 100); // number of files to store before clearing cache
define ('CACHE_CLEAR', 20); // maximum number of files to delete on each cache clear
define ('CACHE_USE', TRUE); // use the cache files? (mostly for testing)
define ('VERSION', '1.25'); // version number (to force a cache refresh)
define ('DIRECTORY_CACHE', '../cache'); // cache directory
define ('MAX_WIDTH', 5000); // maximum image width
define ('MAX_HEIGHT', 3000); // maximum image height
define ('ALLOW_EXTERNAL', FALSE); // allow external website (override security precaution - not advised!)
define ('MEMORY_LIMIT', '128M'); // set PHP memory limit
define ('MAX_FILE_SIZE', 12582912); // file size limit to prevent possible DOS attacks (roughly 12 megabytes)
define ('CURL_TIMEOUT', 10); // timeout duration. Tweak as you require (lower = better)
问题我有的是url图像路径是这样的:
http://mydomain.com/includes/crop.php?src=images/art/urban/alleyway.jpg&h=250&w=958&q=95
我认为启用Cache会是这样的:
http://mydomain.com/cache/a051f7c9e5d039708ac92dece9a07901.jpg
如果我做错了,请告诉我。
干杯 约翰
答案 0 :(得分:1)
据我所知,TimThumb仍然会运行PHP处理,以至少评估是否存在拇指。所以不,它仍然应该在你的img上有相同的src。