Question

我有一个调用MVC操作的jquery例程，该操作将对API URL进行PUT / POST。来自jQuery的调用很好，并且与使用C＃调用API一样有效。当通过Firebug / Fiddler检查时，以JSON格式从API接收响应。

如何将该响应发送回调用jQuery？

我的C＃代码是：

 public string callAPIPut(string ApiUrl, string JsonString)
    {
        WebRequest request = WebRequest.Create(ApiUrl);

        ASCIIEncoding encoding = new ASCIIEncoding();
        byte[] data = encoding.GetBytes(JsonString);

        request.ContentType = "application/json; charset=utf-8";
        request.Method = WebRequestMethods.Http.Put;
        request.ContentLength = JsonString.Length;

        Stream newStream = request.GetRequestStream();
        newStream.Write(data, 0, JsonString.Length);
        newStream.Close();

        return ""; // How do I return the JSON response from the API?
    }

在进行GET时，我可以使用类似下面的内容将响应返回到调用jQuery：

response = (HttpWebResponse)request.GetResponse();
using (StreamReader sr = new StreamReader(response.GetResponseStream()))
{
   serviceResponse = sr.ReadToEnd();
}
return serviceResponse;

我不知道如何在执行Put / Post时返回响应？

Answer 1

public ActionResult CallAPIPut(string ApiUrl, string JsonString)
{
    using (var client = new WebClient())
    {
        client.Headers[HttpRequestHeader.ContentType] = "application/json";
        byte[] data = Encoding.Default.GetBytes(JsonString);
        byte[] result = client.UploadData(ApiUrl, "PUT", data);
        return Content(Encoding.Default.GetString(result), "application/json");
    }
}

或通过包装自定义和可重复使用的操作结果使其更智能，以避免使用基础架构管道混乱控制器：

public class ApiResult : ActionResult
{
    public ApiResult(string apiUrl, string jsonData)
        : this(apiUrl, jsonData, "PUT")
    {
    }

    public ApiResult(string apiUrl, string jsonData, string method)
    {
        ApiUrl = apiUrl;
        JsonData = jsonData;
        Method = method;
    }


    public string ApiUrl { get; private set; }
    public string JsonData { get; private set; }
    public string Method { get; set; }

    public override void ExecuteResult(ControllerContext context)
    {
        var response = context.HttpContext.Response;
        var contentType = "application/json";
        response.ContentType = contentType;
        using (var client = new WebClient())
        {
            client.Headers[HttpRequestHeader.ContentType] = contentType;
            byte[] data = Encoding.Default.GetBytes(JsonData);
            byte[] result = client.UploadData(ApiUrl, Method, data);
            response.Write(Encoding.Default.GetString(result));
        }
    }
}

现在您的控制器操作变为：

public ActionResult CallAPIPut(string apiUrl, string jsonString)
{
    return new ApiResult(apiUrl, jsonString);
}

Answer 2

 Stream newStream = request.GetRequestStream();
 newStream.Write(data, 0, JsonString.Length);
 newStream.Close();

您正在向服务器发布JSON。要获取JSON，您需要发布/放置并使用ResponseStream来读取服务器返回的数据。

样本：

using System;
using System.IO;
using System.Net;
using System.Text;

namespace Examples.System.Net
{
    public class WebRequestGetExample
    {
        public static void Main ()
        {
            // Create a request for the URL. 
            WebRequest request = WebRequest.Create (
              "http://www.contoso.com/default.html");
            // If required by the server, set the credentials.
            request.Credentials = CredentialCache.DefaultCredentials;
            // Get the response.
            WebResponse response = request.GetResponse ();
            // Display the status.
            Console.WriteLine (((HttpWebResponse)response).StatusDescription);
            // Get the stream containing content returned by the server.
            Stream dataStream = response.GetResponseStream ();
            // Open the stream using a StreamReader for easy access.
            StreamReader reader = new StreamReader (dataStream);
            // Read the content.
            string responseFromServer = reader.ReadToEnd ();
            // Display the content.
            Console.WriteLine (responseFromServer);
            // Clean up the streams and the response.
            reader.Close ();
            response.Close ();
        }
    }
}

来自http://msdn.microsoft.com/en-us/library/456dfw4f.aspx

的示例

编辑：您将返回responseFromServer，并在您的Javascript回调中使用它。

如何从MVC发出/发布后获得JSON响应

2 个答案: