我正在撰写此查询,而且我遇到了精神障碍。我一直在自己身边徘徊,令人沮丧。
这是表格:
PO_HEADER(IC_PO_HEADER独特)
IC_PO_HEADER | po_number | revision_number
123 p123 0
456 p123 2
789 p123 48
PO_LINE(IC_LINE_KEY& IC_PO_LINE Unique)
IC_PO_HEADER | po_number | line_rev_no | ic_line_key | ic_po_line
123 p123 0 8246321 214578
123 p123 0 8246322 214579
123 p123 0 8246322 214580
每列大约有150个表,但这些是唯一真正重要的表,因为这是所有内容都要检查的内容,我想复制整行以显示如下:
IC_PO_HEADER | po_number | line_rev_no | ic_line_key | ic_po_line
123 p123 0 8246321 214578
123 p123 0 8246322 214579
123 p123 0 8246323 214580
456 p123 2 8246324 214581
456 p123 2 8246325 214582
456 p123 2 8246326 214583
789 p123 48 8246327 214584
789 p123 48 8246328 214585
789 p123 48 8246329 214586
我打算使用带有选定巢穴的插入物但是我一直在自己跑圈。这是样本数据,PO_HEADER
中有大约15,000条记录,PO_LINE
中有40,000条记录。
伪codeY的:
If PO_HEADER.ic_po_header does not exist in PO_LINE.ic_po_header AND
PO_HEADER.po_number does exist in PO_LINE.po_number
COPY PO_LINE.* where the above is true AND
SET PO_LINE.line_rev_no to PO_HEADER.revision_number (do this until no more PO_HEADER.revision_number's exist that do not meet the criteria)
AUTONUMBER/INCREMENT PO_LINE.ic_line_key AND PO_LINE.ic_po_line
答案 0 :(得分:1)
以下内容将生成您指定的输出。
WITH cte
AS (SELECT ph.IC_PO_HEADER,
ph.PO_NUMBER,
ph.revision_number,
pl.ic_line_key,
pl.ic_po_line,
Row_number()
OVER (
ORDER BY ph.IC_PO_HEADER, IC_LINE_KEY) Rn
FROM PO_HEADER ph
INNER JOIN PO_LINE pl
ON ph.po_number = pl.po_number
)
SELECT t1.IC_PO_HEADER,
t1.PO_NUMBER,
t1.revision_number,
t1.ic_line_key,
t2.ic_line_key + t1.rn - 1,
t2.IC_PO_LINE + t1.rn - 1
FROM cte t1
INNER JOIN cte t2
ON t2.rn = 1
ORDER BY IC_PO_HEADER
使用ROW_NUMBER可以生成AUTONUMBER。通过自我加入CTE,我们可以找到IC_LINE_KEY和IC_PO_LINE的初始值(t2.rn = 1)
答案 1 :(得分:0)
这样的事可能,我没有测试它:
SELECT po_header.*
, 'ic_line_key' = (SELECT max(ic_line_key) FROM PO_LINE) + rank() OVER (ORDER BY newid() ASC)
, 'ic_po_line' = (SELECT max(ic_po_line) FROM PO_LINE) + rank() OVER (ORDER BY newid() ASC)
FROM
PO_HEADER
CROSS JOIN
PO_LINE
WHERE
po_header.po_number = po_line.po_number
AND po_header.ic_po_header <> po_line.ic_po_header