Question

我的阵列出了问题。

$mini_one = array(
    "in" => "#pp1",
    "ot" => "the-r1",
    "fn" => "the_r1()",
    "js" => "$('the-r1').val($('#pp1').val());",
    "ep" => "not tested"
);

$mini_two = array(
    "in" => "#pp1",
    "ot" => "the-r1",
    "fn" => "the_r1()",
    "js" => "$('the-r1').val($('#pp1').val());",
    "ep" => "not tested"
);
//these are different but i just c/p it to show more than one array 
//inside of $big_array

$big_array = array($mini_one,$mini_two);

但是当我用is_array（）测试big_array时它返回false，它在我的foreach循环中也不起作用。

我想知道为什么它不是一个数组？，我怎么能把它变成一个正确的数组？，而且，就像现在一样，它被认为是什么类型的构造？

Answer 1

代码正确

print_r($big_array);

if(is_array($big_array)) echo 'is array'; else echo 'not array';

将输出“is array”

Answer 2

您需要为我们粘贴确切的数组，以了解最新情况。我尝试使用上面的代码片段，它的工作原理。你的$ big_array将如下所示

Array
(
    [0] => Array
        (
            [in] => #pp1
            [ot] => the-r1
            [fn] => the_r1()
            [js] => $('the-r1').val($('#pp1').val());
            [ep] => not tested
        )

    [1] => Array
        (
            [in] => #pp1
            [ot] => the-r1
            [fn] => the_r1()
            [js] => $('the-r1').val($('#pp1').val());
            [ep] => not tested
        )

)

so its multidimensional to loop through it with foreach you need to do the following.
foreach($big_array as $k=>$v) {
foreach($v as $v1) {
echo $v1."<br>";
}
}

为什么这个PHP构造不是数组，顺便问一下，如果不是数组，它是什么？

2 个答案: