PHP递归没有停止

时间:2012-06-06 19:37:00

标签: php recursion

不确定这个递归函数我做错了什么。 我有一个网站树的数组,我正在寻找的页面可以无限​​深。 该功能贯穿所有可能性,但有时在找到正确的“页面”时不会停止。

数组

$haystack = array(
    array("id" => 1,"parent" => 0,"route" => "home","children" => array()),
    array("id" => 2,"parent" => 0,"route" => "news","children" => array()),
    array("id" => 3,"parent" => 0,"route" => "photography","children" => array(
                array("id" => 6,"parent" => 3,"route" => "photography/portraits","children" => array()),
                array("id" => 7,"parent" => 3,"route" => "photography/countries","children" => array()),
                array("id" => 8,"parent" => 3,"route" => "photography/landscapes","children" => array(
                                array("id" => 9,"parent" => 8,"route" => "photography/landscapes/city","children" => array()),
                                array("id" => 10,"parent" => 8,"route" => "photography/landscapes/wilderness","children" => array())
                            )
                )
        )
    ),
    array("id" => 4,"parent" => 0,"route" => "about","children" => array()),
    array("id" => 5,"parent" => 0,"route" => "contact","children" => array()),
);

递归函数

function recurse($needle = -1, $haystack = NULL){
    $_tmp = array();

    foreach($haystack as $key => $item)
    {
        echo $needle ." === ". $item["id"] . "<br/>";

        if((string)$item["id"] === (string)$needle){
            echo "Found: " . $needle . "<br/><br/>";
            $_tmp = $item;
            break;
            //return $item;   <-- this doesn't work either
        } else {
            $_tmp = recurse($needle, $item["children"]);
        }
    }
    return $_tmp;
}

测试用例:

$test = recurse(3);
print_r($test);

$test = recurse(7);
print_r($test);

$test = recurse(9);
print_r($test);

上次测试输出:

9 === 1
9 === 2
9 === 4
9 === 7
9 === 8
9 === 11
9 === 12
9 === 13
9 === 14
9 === 15
9 === 3
9 === 9
Found: 9  <-- should stop here, but continues

9 === 5
9 === 6
Array
(
)

3 个答案:

答案 0 :(得分:3)

它返回但在其他递归帧中继续。 例如,电话:1 - &gt; 2 - &gt; 3 - &gt; 4。 从4返回但3(1 - > 2 - > 3)继续执行循环。

答案 1 :(得分:2)

这是一个稍微修改过的递归函数,可以解决您遇到的问题:

 function recurse($needle = -1, $haystack = NULL){
    static $_tmp = array();

    if (count($_tmp) == 0 && $haystack != NULL && count($haystack) > 0) {
       foreach($haystack as $key => $item) {
          if (count($_tmp) == 0) {
              echo $needle ." === ". $item["id"] . "<br/>\n";

              if((string)$item["id"] === (string)$needle){
                  echo "Found: " . $needle . "<br/>\n";
                  $_tmp = $item;
                  break;
              } elseif (!empty($item["children"])) {
                  echo "calling ". $item["id"]. ".children <br/>\n";
                  $_tmp = recurse($needle, $item["children"]);
              }
          }
       }
    }
    return $_tmp;
}

基本上它声明了一个静态变量$_tmp,它只被初始化一次,然后只有当$_tmp 为空时检查才能处理循环确保停止进一步处理一旦找到 needle

Online working demo of above code

答案 2 :(得分:1)

只有在你没有找到任何关卡的任何东西时,你才能进入阵列,如下所示:

function recurse($needle = -1, $haystack = NULL){
    $_tmp = array();

    foreach($haystack as $key => $item)
    {   
        echo $needle ." === ". $item["id"] . "<br/>";

        if((string)$item["id"] === (string)$needle){
            echo "Found: " . $needle . "<br/><br/>";
            $_tmp = $item;
            break;
            //return $item;   <-- this doesn't work either
        }   
    }   
    if (empty($_tmp))
        foreach($haystack as $key => $item)
        {   
            $_tmp = recurse($needle, $item["children"]);
        }   

    return $_tmp;
}