在我的下面的代码中,我有一个AccessId列表,它存储在树节点的标记中。 如何检查节点(或子节点)中的标签是否在我的列表中?
List<AccessFieldSet> AccessList = new List<AccessFieldSet>();
private void GetRolesAccessData(Int32 RolesId)
{
C_RolesUsers Db = new C_RolesUsers();
AccessList = Db.GetRolesAccessData(RolesId);
foreach (AccessFieldSet Afs in AccessList)
{
foreach (TreeNode node in TreeRoles.Nodes)
{
if (node.Tag == Afs.AccessId.ToString())
{
//Check Node is true ?
}
GetTagChildren(node);
}
}
}
private void GetTagChildren(TreeNode Node)
{
TreeNode ChNode = null;
//TreeFieldSet nodeCat = (TreeFieldSet)Node.Tag;
//Int32 nodeCat = (Int32)Node.Tag;
foreach (AccessFieldSet Afs in AccessList)
{
if (Afs.AccessId.ToString() == Node.Tag)
{
//Check Node is true ?
GetTagChildren(ChNode);
}
}
}
我将我的代码编辑为:
List<AccessFieldSet> AccessList = new List<AccessFieldSet>();
private void GetRolesAccessData(Int32 RolesId)
{
C_RolesUsers Db = new C_RolesUsers();
AccessList = Db.GetRolesAccessData(RolesId);
for (int i = 0; i < TreeRoles.Nodes.Count; i++)
{
CheckedSelectedNodes(i, TreeRoles.Nodes, AccessList);
}
}
private void CheckedSelectedNodes(Int32 i, TreeNodeCollection nodes, List<AccessFieldSet> AccessList)
{
TreeNode node = nodes[i];
for (int j = 0; j < AccessList.Count; j++)
{
foreach (AccessFieldSet Afs in AccessList)
{
if ((int)node.Tag == Afs.AccessId)
{
node.Checked = true;
}
}
}
}
使用新代码,我可以检查节点标记在AccessList中的节点。如何更改ChildNodes(节点的子节点)的代码?
答案 0 :(得分:1)
你可以使用递归来做得非常优雅。
List<AccessFieldSet> accessList = new List<AccessFieldSet>();
private void GetRolesAccessData(Int32 RolesId)
{
C_RolesUsers Db = new C_RolesUsers();
accessList = Db.GetRolesAccessData(RolesId);
foreach (TreeNode node in TreeRoles.Nodes)
{
CheckNodeRecursively(node, accessList);
}
}
private void CheckNodeRecursively(TreeNode node, List<AccessFieldSet> accessList)
{
// Note: You don't need the for loop through 'j'.
foreach (AccessFieldSet afs in accessList)
{
if ((int)node.Tag == afs.AccessId)
{
node.Checked = true;
}
}
foreach (TreeNode childNode in node.Nodes)
{
CheckNodeRecursively(childNode, accessList);
}
}
如果您发现自己经常这样做,可以将递归分解为实用程序方法,并使用Action来改变“每个节点上的动作”逻辑。例如:
public static void ActOnAllRecursively(this TreeNodeCollection nodes, Action<TreeNode> action)
{
foreach (TreeNode node in nodes)
{
ActOnRecursively(node, action);
}
}
public static void ActOnRecursively(this TreeNode node, Action<TreeNode> action)
{
action(node);
foreach (TreeNode node in node.Nodes)
{
ActOnRecursively(node);
}
}
然后你的代码看起来像这样:
List<AccessFieldSet> accessList = new List<AccessFieldSet>();
private void GetRolesAccessData(Int32 RolesId)
{
C_RolesUsers Db = new C_RolesUsers();
accessList = Db.GetRolesAccessData(RolesId);
TreeRoles.Nodes.ActOnAllRecursively((node) =>
{
foreach (AccessFieldSet afs in accessList)
{
if ((int)node.Tag == afs.AccessId)
{
node.Checked = true;
}
}
});
}
最后,您可能会对LINQ发疯并以声明风格编写特定于应用程序的代码:
List<AccessFieldSet> accessList = new List<AccessFieldSet>();
private void GetRolesAccessData(Int32 RolesId)
{
C_RolesUsers Db = new C_RolesUsers();
accessList = Db.GetRolesAccessData(RolesId);
TreeRoles.Nodes.ActOnAllRecursively((node) =>
{
node.Checked = accessList.Any(afs => afs.AccessId == (int)node.Tag);
});
}