如何在jQuery中解析JSON多维数组?

时间:2012-06-04 12:38:52

标签: javascript jquery json parsing

这是我需要解析的JSON:

{"opcode":"groupdetails",
 "status":"success",
 "data":[{"Group ID":5,"Group Name":"data structure","Group Subject":"computer science","Role Type":"Teacher"},{"Group ID":4,"Group Name":"information technology","Group Subject":"computer science","Role Type":"Student"},{"Group ID":6,"Group Name":"data mining","Group Subject":"computer science","Role Type":"Parent"},{"Group ID":7,"Group Name":"dccn","Group Subject":"computer science","Role Type":"Teacher"}]}

我已经尝试并实现了提供的解决方案here,这是在解决方案中定义的JS的实现,仅解析JSON数组

for (var i = 0; i < data.data.length; i++) 
 {
    var object = data.data[i];
     for (property in object) 
     {
        var value = object[property];
        alert(property + "=" + value);
     }
 }

从服务器返回外部JSON 数据,是的,我尝试使用以下代码进行解析,但没有结果:

for (var i = 0; i < data.length; i++) 
{
 var object = data[i];
 for (property in object) 
 {
    var value = object[property];
    alert(property + "=" + value);
 }
}

如何使用单个方法解析整个JSON,而不是单独解析JSON数组?

3 个答案:

答案 0 :(得分:2)

试试这个:

for(var key in data) {
    if(typeof data[key] === "object") {
        for(var i = 0; i < data[key].length; i++) {
            for(var property in data[key][i]) {
                 alert(property + " = " + data[key][i][property]);
            }
        }
    } else if(typeof data[key] === "string") {
        alert(key + " = " + data[key]);
    }
}

答案 1 :(得分:1)

如果您的数据是JSON字符串,则需要先将其解码为object。使用JSON.parse

答案 2 :(得分:0)

我能够访问多级数组中的每个值:

{"dirArray":[{"Dir":{"name":"hr12325","dir_description":"B2B NFIB Field","id":"249"}},{"Dir":{"name":"klk","dir_description":"B2B NFIB klk","id":"251"}}]}
使用

data.dirArray[0].Dir.name
data.dirArray[0].Dir.dir_description

解释here