Question

我有一个ArrayAdapter，我需要获取应用程序的共享首选项才能使用它。我的问题我不能得到共享的偏好。多数民众赞成我的代码：

public class MobileArrayAdapter extends ArrayAdapter<String> {
private final Context context;
private final String[] values;
private static SharedPreferences prefs;
private String firstBtName = "";
private String secondBtName = "";
private String thirdBtName = "";


public MobileArrayAdapter(Context context, String[] values) {
    super(context, R.layout.list, values);
    this.context = context;
    this.values = values;

}

@Override
public View getView(int position, View convertView, ViewGroup parent) {

    prefs = getSharedPreferences("MYPREFS", 0); // ERROR **************

    LayoutInflater inflater = (LayoutInflater) context
        .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View rowView = inflater.inflate(R.layout.list, parent, false);
    TextView textView = (TextView) rowView.findViewById(R.id.label);
    textView.setText(values[position]);

eclips说我没有那种方法...... 我能做什么？谢谢！

Answer 1

您的错误是因为ArrayAdapter没有getSharedPreferences()方法，请更改给您错误的行：

prefs = context.getSharedPreferences("MYPREFS", 0);

Answer 2

您应该在构造函数中获得共享的首选项。您的构造函数应如下所示

public MobileArrayAdapter(Context aplicationContext, String[] values) {
    super(context, R.layout.list, values);
    this.context = context;
    this.values = values;
    prefs= aplicationContext.getSharedPreferences("MYPREFS", 0);
}

如何在扩展ArrayAdapter <string> </string>的类中获取共享首选项

2 个答案: