Question

我在下面有3个选择语句，每个语句创建完全相同的计算列，然后我计算所有的是和计算列中的所有不是。目前它显示区域3次，旁边有3个结果。我希望它显示区域一次，包含3个新列，总计为

我有：

region1 computedCol1

region1 computedCol2

region1 computedCol3

region2 computedCol1

region2 computedCol2

region2 computedCol3

我想：

Region1,  computedCol1, computedCol2, computedCol3

Region2,  computedCol1, computedCol2, computedCol3

Region3,  computedCol1, computedCol2, computedCol3

如果我使用“all all”，我只会得到：

region1 computedCol1

region2 computedCol1

region3 computedCol1

SELECT a.region, COUNT(*) AS [computedCol1]    
(
SELECT  DISTINCT table1.serial1, table1.serial2, region,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)a
    WHERE region in (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000',
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in  ('no')
    GROUP BY a.region

union

SELECT b.region, COUNT(*) AS [computedCol2], region   
(
SELECT  DISTINCT table1.serial1, table1.serial2,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)b
    WHERE region in     (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000'
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in ('yes')
    group by b.region

union

SELECT c.region, COUNT(*) AS [computedCol3], region   
(
SELECT  DISTINCT table1.serial1, table1.serial2,
    CASE WHEN table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol1],
    CASE WHEN table3.serial2 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol2],
    CASE WHEN table3.serial2 IS NULL AND table2.serial1 IS NULL THEN 'No' ELSE 'Yes' END AS [computedCol3]

FROM    table1
        LEFT JOIN table2
            ON table2.serial1 = table1.serial1
        LEFT JOIN dbo.EPG
            table3.serial2 = table1.serial2
)c
    WHERE region in     (
        '37000','38000','39000','41000','42000','43000','44000','46000','45000','51000','52000','53000','54000'
        '55000','56000','57000','58000','59000','61000','62000','63000','64000','65000','66000','67000','68000',
        '69000','30000','33000','36000','34000','35000','31000','32000','N/A'   )
and [CCA Match Org] in ('yes', 'no')
    group by c.region

Answer 1

这就是UNION在所有数据库中的工作方式。它不会创建新列，它会连接所有行。

使用PIVOT运算符将行转换为列。本质上，PIVOT按非旋转列（在本例中为Region）对行进行分组，并将聚合应用于每个生成的列。

Answer 2

您可以像其他答案建议一样使用枢轴，或者您可以使用SUM结合CASE来获得相同的结果。如果你有很多计算字符，这就变得很痛苦。

我正在使用Oracle作为我的示例，但该概念应转换为SQLServer。

示例：

SELECT 'A' region, 1 col_num, 10 computed_value FROM DUAL
UNION
SELECT 'A' region, 2 col_num, 11 computed_value FROM DUAL
UNION
SELECT 'A' region, 3 col_num, 12 computed_value FROM DUAL
UNION
SELECT 'B' region, 1 col_num, 20 computed_value FROM DUAL
UNION
SELECT 'B' region, 2 col_num, 21 computed_value FROM DUAL
UNION
SELECT 'B' region, 3 col_num, 22 computed_value FROM DUAL

返回：

REGION  COL_NUM COMPUTED_VALUE
A           1   10
A           2   11
A           3   12
B           1   20
B           2   21
B           3   22

如果您将该查询嵌套如下：

SELECT     region,
           SUM (CASE col_num WHEN 1 THEN computed_value ELSE NULL END) compulated_1,
           SUM (CASE col_num WHEN 2 THEN computed_value ELSE NULL END) compulated_2,
           SUM (CASE col_num WHEN 3 THEN computed_value ELSE NULL END) compulated_3
    FROM   (SELECT 'A' region, 1 col_num, 10 computed_value FROM DUAL
            UNION
            SELECT 'A' region, 2 col_num, 11 computed_value FROM DUAL
            UNION
            SELECT 'A' region, 3 col_num, 12 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 1 col_num, 20 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 2 col_num, 21 computed_value FROM DUAL
            UNION
            SELECT 'B' region, 3 col_num, 22 computed_value FROM DUAL)
GROUP BY   region

给你：

REGION  COMPULATED_1    COMPULATED_2    COMPULATED_3
A           10          11           12
B           20          21           22

联合同一个表，该表在同一行中提供3个单独的结果和列

2 个答案: