我试图根据派生的设置类自动实例化正确的派生类。
这里我有主基类和基本设置类
public abstract class BaseClass
{
public BaseClass() { }
public abstract BaseClassSettings Write();
}
public class BaseClassSettings
{
}
现在这里是我的派生类及其设置类
public class DerivedFoo : BaseClass
{
public DerivedFoo(DerivedFooSettings settings)
{
// Apply settings
}
public override BaseClassSettings Write()
{
DerivedFooSettings settings = new DerivedFooSettings();
return settings;
}
}
public class DerivedFooSettings : BaseClassSettings
{
}
public class DerivedBar : BaseClass
{
public DerivedBar(DerivedBarSettings settings)
{
// Apply settings
}
public override BaseClassSettings Write()
{
DerivedBarSettings settings = new DerivedBarSettings();
return settings;
}
}
public class DerivedBarSettings : BaseClassSettings
{
}
我可以将所有派生类设置保存在一个数组中
DerivedFoo foo = new DerivedFoo();
DerivedBar bar = new DerivedBar();
BaseClassSettings[] s = new BaseClassSettings[2];
s[0] = foo.Write();
s[1] = bar.Write();
以XML格式序列化为光盘。
如何根据派生的设置类自动实例化派生类?
因此,如果数组元素是DerivedBarSettings类,则创建DerivedBar类的新实例。
我想这样做而不使用越来越多的else if语句,具体取决于类的数量。
if (BaseClassSettings is DerivedFooSettings)
new DerivedFoo(settings)
else if (BaseClassSettings is DerivedBarSettings)
new DerivedBar(settings)
如何做到这一点?
=============================================== ================================
[编辑]
这是我正在使用的内容:
[
XmlInclude(typeof(DerivedSettingsClassA)),
XmlInclude(typeof(DerivedSettingsClassB)),
XmlInclude(typeof(DerivedSettingsClassC)),
XmlInclude(typeof(DerivedSettingsClassD)),
XmlInclude(typeof(DerivedSettingsClassE)),
]
public abstract class BaseSettingsClass
{
public abstract DerivedClass Load(Game1 game, OutputDimensionSettings settings);
}
唯一的缺点是我必须为所有派生类明确定义XmlInclude。
答案 0 :(得分:1)
这是家庭作业吗?
这是一种方式(还有其他可能性):
public abstract class BaseClass
{
public abstract BaseClassSettings Write();
}
public abstract class BaseClassSettings
{
public abstract BaseClass CreateCorrespondingInstance();
}
然后:
public class DerivedFoo : BaseClass
{
public DerivedFoo(DerivedFooSettings settings)
{
// Apply settings
}
public override BaseClassSettings Write()
{
DerivedFooSettings settings = new DerivedFooSettings();
return settings;
}
}
public class DerivedFooSettings : BaseClassSettings
{
public override BaseClass CreateCorrespondingInstance()
{
return new DerivedFoo(this);
}
}
但看起来你可以从仿制药中受益!
答案 1 :(得分:0)
我不确定仿制药在这里会有多大帮助。泛型用于推迟或约束在编译时直到未知的类型。你在做什么是在不相关的类型之间建立关系。这可以通过自定义属性和一些反射来完成。
首先我们的自定义属性:
[System.AttributeUsage(System.AttributeTargets.Class)]
public class BaseClassLinkAttribute : System.Attribute
{
public System.Type LinkedType { get; set; }
public BaseClassLinkAttribute(Type linkedType)
{
// Probably wat to make sure type is derrived from BaseClass
LinkedType = linkedType;
}
}
现在我们在基类中添加一个静态方法,在自定义属性中创建该类型的实例:
public abstract class BaseClass
{
public BaseClass()
{
}
public abstract BaseClassSettings Write();
public static BaseClass CreateFromSettings(BaseClassSettings settings)
{
Attribute attr = Attribute.GetCustomAttribute(settings.GetType(), typeof(BaseClassLinkAttribute));
// Check for null here and throw exception if attribute can't be found in prduction code
BaseClassLinkAttribute linkAttribute = (BaseClassLinkAttribute)attr;
// This is only going to work if class implements a constructor
// that take a base settings class
return (BaseClass)Activator.CreateInstance(linkAttribute.LinkedType,settings);
}
}
现在我们要做的就是使用我们想要创建的类的属性标记settings类。
[BaseClassLink(typeof(DerivedFoo))]
public class DerivedFooSettings : BaseClassSettings
{
}
因此,给定一个设置类,我们现在可以创建关联类:
DerivedFooSettings x = new DerivedFooSettings();
BaseClass y = BaseClass.CreateFromSettings(x);
Console.WriteLine(y.GetType().FullName);
这将为您提供Namespace.DerivedFoo的输出。
当然这里有一些限制,derrived类必须实现一个构造函数,它接受设置类或激活将失败。我认为我们可以通过一些工作来摆脱attrbiute并使用泛型传递类型。但是,您仍然需要在类型之间创建链接。