Question

我正在努力解决这个问题，我正在尝试构建一个具有多个级别的简单菜单树

RootFolder
- First Sub Folder
-- First Sub Sub Folder
--- First Sub Sub Sub Folder
--- First Sub Sub Sub Sub Folder
- Second Sub Folder
- Second Sub Sub Folder

我的XML非常简单（不是正确的值）

<OrgFolderDetails>
    <FolderName>Main Folder</FolderName>
    <TheChildren>
        <OrgFolderDetails>
            <FolderName>First Sub Folder</FolderName>
            <TheChildren>
                <OrgFolderDetails>
                    <FolderName>First Sub Sub Folder</FolderName>
                    <TheChildren>
                        <OrgFolderDetails>
                            <FolderName>First Sub Siub Sub Folder</FolderName>
                            <TheChildren>
                                <OrgFolderDetails>
                                    <FolderName>First Sub Sub Sub Sub Folder</FolderName>
                                    <TheChildren/>
                                </OrgFolderDetails>
                            </TheChildren>
                        </OrgFolderDetails>
                    </TheChildren>
                </OrgFolderDetails>
            </TheChildren>
        </OrgFolderDetails>
        <OrgFolderDetails>
            <FolderName>Second Sub Folder</FolderName>
            <TheChildren>
                <OrgFolderDetails>
                    <FolderName>Second Sub Sub Folder</FolderName>
                    <TheChildren/>
                </OrgFolderDetails>
            </TheChildren>
        </OrgFolderDetails>
    </TheChildren>
</OrgFolderDetails>

我使用过jQuery的.filter（）和。 find（）每个（）没有任何成功，它没有给我很好的破折号来指示我在哪个级别，它只是吐出文件夹名称。

我遍历的代码

 $(data).find("FolderName").each(function(){
             var folderName = $(this).text();

            $("#folderLevels").append(folderName+"<br/>");
         });

Answer 1

好的，所以根据我的理解，我们需要建立一个菜单，其中包含一定数量的前面破折号，具体取决于孩子的等级。幸运的是，jQuery让这很容易。

$(data).find("FolderName").each(function(){ 
    var levels = $(this).parents("OrgFolderDetails").size();
    var text = $(this).text();
    var html = "";

    for(var j=0; j < levels; j++){
        html += "-";    
    }
    html += " "+text+"</br>"; //add in that space after the dashes, and the <br>

    $("#folderLevels").append(html);
});

希望有所帮助。这里的主要帮助是parents()方法。 http://api.jquery.com/parents

Answer 2

我想你会想要使用递归函数。

var s = getNestedString($(data), 0);

function getNestedString(d, level) {
    // get the name of current node
    var s = d.children("FolderName").text() + "<br/>";

    // prepend with dashes for inner levels
    for (var i=0 ; i<level ; i++) {
        s = "-" + s;
    }

    // get children and call this function recursively (incrementing level)
    var ch = d.children("TheChildren").children("OrgFolderDetails");
    for (var i=0 ; i < ch.length ; i++) {
        s = s + getNestedString(ch[i], level+1);
    }

    // return string for current and nested nodes
    return s;
}

jquery ajax响应，遍历XML来构建嵌套菜单树

2 个答案: