Question

我需要在PHP代码中引入JavaScript警报函数show_alert()。如何做到这一点？

script type="text/javascript">
        function show_alert() {
            var msg = "No solution found.";
            alert(msg);
        }
</script>
<?php
//...
    $outputs = -1;
    if ($outputs == -1) {
        echo '<script type="text/javascript"> show_alert(); </script>';
    } else {
        ?>
        <table width="100%">
            <tr>
                <td width="100%"> 
                    <div class="scrollbar" id="chart">
                        <img src="ganttchart.php">
                    </div>
                </td>
            </tr>
        </table>
    <?php
    }
?>

Answer 1

内嵌JavaScript需要位于<script>标记内。只需在有效的地方输出它们。请注意，尽管如此，您不能以这种方式影响PHP代码的操作。

Answer 2

试试这个，它回显show_alert（）;用PHP：

<script type="text/javascript">
    function show_alert() {
    var msg = "No solution found";
    alert(msg);
    }
</script>

<?php
//...

$output = run_function();
if ($output == -1) {
   echo '<script type="text/javascript"> show_alert(); </script>';
}
?>

Answer 3

使用此

<script type="text/javascript">
         show_alert();
    </script>

所以这样

$output = run_function();
if ($outputs == -1) {
?>
<script type="text/javascript">
             show_alert();
        </script>
<?php
}
?>

Answer 4

我建议

    $msg = "My message";
    echo "<script type=\"text/javascript\"> alert($msg); </script>";

你是对的大卫

Answer 5

<?php
    $output = run_function();
    if ($outputs == -1) {
        echo "<script type='text/javascript'>alert("No Solution Found");</script>"
    }
?>

如何在PHP代码中引入JavaScript警报窗口

5 个答案: