Question

我非常感谢您对我的任何反馈和时间。

我正在使用一个PHP页面来查询带有1个表的数据库并且似乎被卡住了。 SQL不是我的强项，所以我寻求一些帮助。我正在使用附带MYSQL的PHP工作。

数据库

我有一个表“Product”，其中包含：

1ID, 2Product Description, 3Price, 4Category, 5Size, 6Price-Category

我想运行一个查询来确定哪些产品符合尺寸（完全匹配）和Price-Catgory（等于或高于）。因此我考虑了以下过程：

A - run queries to identify different products by Category (one for Category A, one for Category B)
B - compare query A and B by Size and Price-Category
C - Display Results by ID for Category A

我想输出查询A产品的每个ID的结果：

1ID|2Product Description|3Price|4Category|5Size|6Price-Category|7Query B Details
1   Product              100    Cat       100   1               ID, Product. etc.
                                                                ID, Product. etc.
                                                                ID, Product. etc.

2   Product              200    Cat       100   2               ID, Product. etc.
                                                                ID, Product. etc.
                                                                ID, Product. etc.

关于如何构建这个的任何想法？

提前致谢！

我到目前为止尝试过的代码（我目前试图从两个表中获取它们，但最初它们只是一个!!!!）

$query = "SELECT betten.m3, betten.Shortcode, betten.CodePDT, betten.PVCons, betten.CAT, betten.size1, betten.size2, betten.m3, betten.SIZE, betten.PRICERANGE, som.CodePDT2, som.Shortcode2, som.PRICECLASS, som.PVCons2, som.CAT2, som.size1a, som.size2a, som.m3a, som.SIZETWO FROM betten LEFT JOIN som ON betten.m3 = som.m3a ORDER BY CodePDT ";  
        $result = mysql_query($query) or die(mysql_error());
        // Print out the contents of each row into a table 
        while($row = mysql_fetch_array($result)){
            echo "<tr><td>";
            echo $row['CodePDT']. "</td><td>".$row['Shortcode']. "</td><td>". $row['PVCons']."</td><td>". $row['CAT']. "</td><td>". $row['SIZE']. "</td><td>". $row['m3']."</td><td>". $row['PRICERANGE']. "</td><td>". $row['CodePDT2']. "</td><td>". $row['Shortcode2']. "</td><td>". $row['PVCons2']. "</td><td>". $row['CAT2']. "</td><td>". $row['SIZETWO']. "</td><td>". $row['m3a']. "</td><td>". $row['PRICECLASS']. "</td><td>";
            echo "</td></tr>";
        }

更新：

这适用于GROUP_CONT。没有，我得到的结果，但逐行。使用GROUP_CONT我收到错误“检查与您的MySQL服务器版本相对应的手册，以便在'GROUP_CONCAT（som.S ....）附近使用正确的语法。

SELECT `betten`.*, `som`.*
FROM betten
    LEFT JOIN som ON betten.m3 = som.m3a    
    WHERE SIZE LIKE SIZETWO    
GROUP_CONCAT(som.Shortcode2) AS Dude
    GROUP BY betten.CodePDT    
    ORDER BY CodePDT ASC

Answer 1

通过以下方式实现：

$query = ("SELECT
    r.rangename as rRangename,  /* Get Ranges from Rangetable */
    r.rangevalue as rRangevalue,
    m.name as mName, /* Get Fields from main Products */
    m.Code as mCode,
    m.Range as mRange,
    SUBSTRING_INDEX(GROUP_CONCAT(f.productcode ORDER BY f.index_id ASC SEPARATOR ','),',',3) as fCodes, /* Get Fields from Cross Selling and list them seperatly */
    SUBSTRING_INDEX(GROUP_CONCAT(f.name ORDER BY f.index_id ASC SEPARATOR ','),',',3) as fNames,
    SUBSTRING_INDEX(GROUP_CONCAT(f.range ORDER BY f.index_id ASC SEPARATOR ','),',',3) as fRanges

FROM
    crossproducts f
JOIN /* Match main products with cross via m3 */
    mainproduct m
ON
    m.m3 = f.m3 
JOIN /* Match ranges and assign values for cross */
    ranges r
ON
    r.rangename = f.range
JOIN /* Match ranges and assign values for main */
    ranges s
ON
    s.rangename = m.Range
WHERE /* Only get Items that are equal or higher price range */
    r.rangevalue - s.rangevalue > -1

GROUP BY /* And finally group them by main Product Code */
    m.Code;");

PHP MYSQL - 多个查询和输出

1 个答案: