我有许多数据库,外键(非正式)字段名和主键字段名对于以下代码中可见的样本是相同的。
CREATE TABLE Customer(
CustomerId int PRIMARY,
CustomerName varchar(200),
...
)
CREATE TABLE Invoice(
InvoiceID int PRIMARY KEY,
InvoiceType int ,
CustomerID int)
CREATE TABLE InvoiceDet(
InvoiceDetId int PRIMARY KEY,
InvoiceId int ...)
我想要一个程序(或脚本)来读取我的表,列并创建外键引用。应该生成关系:Customer.CustomerId<=>Invoice.CustomerID
和
InvoiceDet.InvoiceId<=>Invoice.InvoiceId
答案 0 :(得分:2)
这是一个巨大的任务,用于创建此类自动脚本,尤其是对于您提到的所有数据库。您应该考虑聘请一些具有perl / python知识的优秀DBA为您做这件事。
使用最少量的检查(密钥中的列数和列的类型不进行交叉检查),以下可能是PostgreSQL的concept proof:
WITH colnames(oid,colnum,colname) AS (
SELECT a.attrelid AS oid, a.attnum AS colnum, a.attname AS colname
FROM pg_attribute a WHERE a.attnum > 0 AND NOT a.attisdropped),
pkcols(oid,colnum) AS (
SELECT c.conrelid AS oid, unnest(c.conkey)
FROM pg_constraint c
WHERE contype = 'p'),
pks(oid,colnum,colname) AS (
SELECT pkc.oid, pkc.colnum, cn.colname
FROM pkcols pkc
JOIN colnames cn ON pkc.oid = cn.oid AND pkc.colnum = cn.colnum),
pktabs AS (
SELECT t.oid AS oid, n.nspname AS sname, t.relname AS tname,
pks.colnum AS colnum, pks.colname AS colname
FROM pg_class t
JOIN pg_namespace n ON n.oid = t.relnamespace
JOIN pks ON pks.oid = t.oid
WHERE t.relkind = 'r'),
coltabs AS (
SELECT t.oid AS oid, n.nspname AS sname, t.relname AS tname,
cn.colnum AS colnum, cn.colname AS colname
FROM pg_class t
JOIN pg_namespace n ON n.oid = t.relnamespace
JOIN colnames cn ON cn.oid = t.oid
WHERE t.relkind = 'r')
SELECT 'ALTER TABLE '||quote_ident(ct.sname)||'.'||quote_ident(ct.tname)||
' ADD FOREIGN KEY ('||string_agg(quote_ident(pk.colname),',')||
') REFERENCES '||
quote_ident(pk.sname)||'.'||quote_ident(pk.tname)||' ('||
string_agg(quote_ident(pk.colname),',')||');'
FROM pktabs pk
JOIN coltabs ct ON pk.oid != ct.oid AND pk.colname = ct.colname
GROUP BY pk.sname,pk.tname,ct.sname,ct.tname;