Question

这是我的代码......

if($_SERVER['REQUEST_URI'] == '/shop/category/handheld-thermal-imaging/')
{
echo
'<div class="current-mark"></div><div class="top-level"><a href="/shop/category/handheld-thermal-imaging/">HANDHELD<br />THERMAL IMAGING</a></div>';
} 

else if($_SERVER['REQUEST_URI'] == '/shop/category/mobile-imaging/')
{
echo
'<div class="current-mark"></div><div class="top-level"><a href="/shop/category/mobile-imaging/">MOBILE IMAGING</a></div>';
}

基本上，此代码会显示不同的左侧网站导航，具体取决于您在网站上的哪个页面。它使用PHP REQUEST_URI功能通过页面的URL检测您所在的页面。

我的问题是，如何让代码检测同一导航片段的多个网址？

我试过这段代码......

if($_SERVER['REQUEST_URI'] == '/shop/category/handheld-thermal-imaging/' , '/shop/iphone-thermal-imaging-adapter/')
{

但该代码似乎不起作用。基本上我想弄清楚的是我如何使用REQUEST_URI'if'语句的多个URL。提前谢谢！

Answer 1

将网址放入数组然后...... if(in_array($_SERVER['REQUEST_URI'],$array))

Answer 2

你应该......切换到一个switch语句，它既简洁又提供此选项：

switch($_SERVER['REQUEST_URI']) {
    case '/shop/category/handheld-thermal-imaging/':
        // THERE IS NO CODE AT ALL HERE!
        // The absence of a "break;" causes control to "fall through" to the next
    case '/shop/iphone-thermal-imaging-adapter/':
        echo "something common for the thermal imaging urls";
        break;
    case 'some other url':
        echo "something for the url that stands alone";
        break;
}

Answer 3

我使用OR语句进行了多个URL检查

<?php 

   if ((strpos($_SERVER['REQUEST_URI'], 'contact.php')  || strpos($_SERVER['REQUEST_URI'], 'register.php') || strpos($_SERVER['REQUEST_URI'], 'login.php')) === false) { 
     echo "show";  
   } else { 
     echo "hide";  
   } 

?>

Answer 4

您可以在条件中使用“OR”语句：

if($_SERVER['REQUEST_URI'] == "whatever" || $_SERVER['REQUEST_URI'] == 'something else")
{

}

如何在PHP REQUEST_URI语句中使用多个URL？

4 个答案: