Question

我只是复制粘贴tastypie示例代码以了解它是如何工作的。代码如下。我也做了modelclass Entry。当我在url上运行http://localhost:8000/api/v1/时会抛出错误

# myapp/api/resources.py
from django.contrib.auth.models import User
from tastypie.authorization import Authorization
from tastypie import fields
from tastypie.resources import ModelResource, ALL, ALL_WITH_RELATIONS
from myapp.models import Entry


class UserResource(ModelResource):
    class Meta:
        queryset = User.objects.all()
        resource_name = 'user'
        excludes = ['email', 'password', 'is_active', 'is_staff', 'is_superuser']
        filtering = {
        'username': ALL,
    }


class EntryResource(ModelResource):
    user = fields.ForeignKey(UserResource, 'user')

class Meta:
    queryset = Entry.objects.all()
    resource_name = 'entry'
    authorization = Authorization()
    filtering = {
        'user': ALL_WITH_RELATIONS,
        'pub_date': ['exact', 'lt', 'lte', 'gte', 'gt'],
    }

urls.py

from django.conf.urls.defaults import *
from tastypie.api import Api
from myapp.api.resources import EntryResource, UserResource

v1_api = Api(api_name='v1')
v1_api.register(UserResource())
v1_api.register(EntryResource())

urlpatterns = patterns('',
    # The normal jazz here...
    (r'^blog/', include('myapp.urls')),
    (r'^api/', include(v1_api.urls)),
 )

正在抛出消息“没有名为urls的模块”。有什么想法吗？

Answer 1

你应该尝试：

(r'^api/', include('v1_api.urls')),

Answer 2

此错误正在发生，因为myapp包中没有名为urls.py的模块。在myapp包中创建一个模块urls.py

Answer 3

而不是

from django.conf.urls.defaults import *

您可以尝试像这样导入

from django.conf.urls import *

django-tastypie中没有名为urls的模块

3 个答案: